Question

A rectangle has length 10 feet and width 6 feet. It is enlarged to a similar rectangle with length 18 feet. What is the new width?

Answer 1

Answer:

The new width of the rectangle is 10.8 feet.

Step-by-step explanation:

Given:

Length of a rectangle 10 feet and width 6 feet. Length of the enlarged 18 feet.

Now, length of small rectangle (l) = 10 feet, width of small rectangle (w) = 6 feet, length of enlarged rectangle (L) = 18 feet and let the width of enlarged rectangle  = $x$.

When enlarging the first rectangle, will be maintaining the aspect ratio of the first rectangle. The rectangles representing the outer edges of the first and enlarged rectangles will be similar. Using this fact, we can set up a proportion and solve.

So,

$10:6::18:x$

$\frac{10}{6} =\frac{18}{x}$

Multiplying with $x$ on both the sides we get,

$\frac{10x}{6}=18$

Multiplying with 6 on both sides we get,

$10x=108$

And, now dividing by 10 on both the sides we get the width,

$x=10.8$

Width = 10.8 feet.

Therefore, the new width of the rectangle is 10.8 feet.