Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
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Answer:
90°
Step-by-step explanation:
Angle C = arccos((84²+13²-85²)/(2×84×13))
= arccos(0/2184)
= arccos(0)
= 90°
Answered by GAUTHMATH
2345
2156
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0189
189 marbles left
None of the above
My mom just helped me with it, so I don't know if it's exactly alright. She said it was 20, but theres no 20 as I checked, and I don't know if she didn't right. I got a whole 25.
ANSWERS I THINK
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I think its mainly a,e, or b. Mainly b?
Answer:
The mass of the object is 2.6 grams
Step-by-step explanation:
The density of an object is the ratio between its mass and its volume
The equation of the is d =
, where
Let us use this equation to solve the question
∵ An object has a density of 1.3 g/cm³
∴ d = 1.3 g/cm³
∵ Its volume is 2 cm³
∴ V = 2 cm³
→ Substitute them in the equation of the denisty above
∵ 1.3 = 
→ Multiply both sides by 2
∴ 2 × 1.3 = 2 × 
∴ 2.6 = m
∴ The mass of the object is 2.6 grams