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Ierofanga [76]
3 years ago
9

For dessert, she prepares to bake a delicious apple pie. During one of the steps, she

Chemistry
2 answers:
Leno4ka [110]3 years ago
6 0

Answer:

heating the sugar

Explanation:

Step2247 [10]3 years ago
4 0

Answer:

softening butter...

Explanation:

that sounds the best because the butter be melting

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What is the percent composition by mass of aluminum in Al2(SO4)3 (gram-formula mass = 342 grams/mole)?
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The atomic mass of Aluminum is around 27 amu. There are two aluminum atoms, so it takes 54 amu. The gram-formula states that 1 mole of this compound has 342 grams. By definition, this means that the total amu of this compound is 342. Therefore, we divide 54 by 342 to get around 15.8 %. 

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Which is true of a solute dissolved in a solvent?
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The solute increased to the boiling point of the solvent. In shorter terms it's raising to the boiling point. 
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Suppose you have an aqueous solution containing 158.2 g KOHper
postnew [5]

Answer:

1132.8 ml of water

Explanation:

you have an aqueous solution contains 158.2 g KOH per liter

so concentration =158.2/56 = 2.825M

Molarity =2.825

that means you have 2.825 moles of KOH in 1.00L solution

Mass of Soluet(KOH)= 152.8g

Volume of solution= 1.00L

density of solution= 1.13g/cm3 =1.13g/ml

therefore mass of solution = VolumeX density = 1000mL X 1.13g/ml.=1130g

Mass of solvent(water)= mass of solution- mass of solute(KOH)=1130-152.8= 997.2g

Molality= moles of solute/mass of solvent(Kg)

=2.825/(997.2/1000)= 2.832molal

to prepare a 0.250 molal solution of KOH, starting with 100.0ml ofthe orginal solution

0.250*X =2.832 *100

X = 1132.8 ml of water you have to add

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