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11111nata11111 [884]
3 years ago
14

A 0.1014 g sample of a purified CHO compound was burned in a combustion apparatus and produced 0.1486 g CO2 and 0.0609 g of H2O.

What is the empirical formula of this CHO compound? Enter as C#H#O#, e.g. C2H3O2

Chemistry
1 answer:
kirza4 [7]3 years ago
4 0

Answer: the empirical formula is CH2O

Explanation:Please see attachment for explanation

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So, a gas, and an
valina [46]

Answer:

d) cut the large sized Cu solid into smaller sized pieces

Explanation:

The aim of the question is to select the right condition for that would increases the rate of the reaction.

a) use a large sized piece of the solid Cu

This option is wrong. Reducing the surface area decreases the reaction rate.

b) lower the initial temperature below 25 °C for the liquid reactant, HNO3

Hugher temperatures leads to faster reactions hence this option is wrong.

c) use a 0.5 M HNO3 instead of 2.0 M HNO3

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d) cut the large sized Cu solid into smaller sized pieces

This leads to an increased surface area of the reactants, which leads to an increased rate of the reaction. This is the correct option.

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3 years ago
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HACTEHA [7]

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3 0
2 years ago
Solid carbon (C) can burn in oxygen (O2). Select
babunello [35]

Answer:

OCO

Another way of writing CO₂

Explanation:

A reaction equation has <u>reactants on the left</u> and <u>products on the right</u>.

The reactants are carbon and oxygen. The product is carbon dioxide.

C + O₂ → CO₂

You might see the equation both ways.

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C + O₂ in the products would mean no reaction has occurred. The problem can <u>solid carbon can burn in oxygen</u>, so a reaction will occur. For no reaction, you would put "NR" in the products.

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3 0
3 years ago
How many moles of ba(oh)2 are present in 275 ml of 0.200 m ba(oh)2?
DENIUS [597]
You have to put your attention to the unit of concentration. It is expressed in terms of molarity, which is represented in M. It is the number of moles solute per liter solution. So, you simply have to multiply the molarity with the volume in liters.

Volume = 275 mL * 1 L/1000 mL = 0.275 L
<em>Moles Ba(OH)₂ = (0.200 M)(0.275 L) = 0.055 mol</em>
6 0
3 years ago
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