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2 years ago

Which statement describes one feature of Rutherford model of the atom

Chemistry

1 answer:

serious [3.7K]2 years ago

6 0

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<em><u>The Rutherford model shows that an atom is mostly empty space, with electrons orbiting a fixed, positively charged nucleus in set, predictable paths.</u></em>

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7 organic compounds of plant origin

Nat2105 [25]

Explanation:

Among the numerous types of organic compounds, four major categories are found in all living things carbohydrates, lipids, proteins and nucleic acids.

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3 years ago

What is the mass in grams of 2.0 moles of NO2

JulsSmile [24]

Molar mass NO₂ = 46.0 g/mol

1 mole -------- 46.0 g
2.0 moles ----- ?

Mass (NO₂) = 2.0 x 46.0 / 1

=> 92.0 g

hope this helps!

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3 years ago

Read 2 more answers

When an apple or banana is cut, a chemical reaction with air causes the flesh to turn brown. Placing the fruit in a cold place,

PIT_PIT [208]

Apples turn brown when exposed to air because it undergoes aerial oxidation. Due to this, when the inside of the apple is exposed to the air containing oxygen and water, it turns brown. When apple is uncut, skin of the apple protects it from this process.

If the peeled apple in kept in the refrigerator, the oxidation reaction is greatly slowed down. This is because, rate of chemical reaction decreases with temperature. Hence, in refrigerator it would take several days for it to turn brown.

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3 years ago

First-order reaction that results in the destruction of a pollutant has a rate constant of 0.l/day. (a) how many days will it ta

Klio2033 [76]

Rate equation for first order reaction is as follows:

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}$

Here, k is rate constant of the reaction, t is time of the reaction, $A_{0}$ is initial concentration and $A_{t}$ is concentration at time t.

The rate constant of the reaction is $0.1 day^{-1}$ .

(a) Let the initial concentration be 100, If 90% of the chemical is destroyed, the chemical present at time t will be 100-90=10, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{10}=23.03 days$

Thus, time required to destroy 90% of the chemical is 23.03 days.

(b) Let the initial concentration be 100, If 99% of the chemical is destroyed, the chemical present at time t will be 100-99=1, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{1}=46.06 days$

Thus, time required to destroy 99% of the chemical is 46.06 days.

(c) Let the initial concentration be 100, If 99.9% of the chemical is destroyed, the chemical present at time t will be 100-99.9=0.1, on putting the values,

$t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{0.1}=69.09 days$

Thus, time required to destroy 99.9% of the chemical is 69.09 days.

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2 years ago

Can somebody help please to balance those I couldn’t balance it

scZoUnD [109]

Answer:

(NH4)2Cr2O7——>Cr2O7+N2+4H2O

6CO2+6H2O——>C6H12O6+6O2

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2 years ago