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blsea [12.9K]
3 years ago
7

Does a large or small body cool faster?

Chemistry
1 answer:
Nataly [62]3 years ago
8 0

Answer:

SO… The larger wire looses heat energy faster, however the smaller wire decreases temperature faster. ... Their surface area is much larger in proportion to their body mass and they lose heat through their skin when it is cold and they gain heat through their skin when it is hot much faster than an adult does.

Explanation:

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Consider the following balanced thermochemical equation for a reaction sometimes used for H₂S production: 1/8 S₈(s) + H₂(g) → H₂
castortr0y [4]

ΔH = -15.78 KJ when 25.0 g of S₈ reacts.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

The given reaction balanced equation is:

1/8 S₈(s) + H₂(g) → H₂S(g)       ΔH = -20.22kj

Now,

When 1 mol will react, then ΔH = -20.2 × 8

                                                   = -161.6 KJ

When 1 mol of S8 = 8 × 32 g

                             = 256 g

When 256g of S8 react ΔH = -161.6 KJ

When 1 g reacts, ΔH = \frac{-161.6}{256}

                                  =- 0.63125 KJ

When 25 g reacts, ΔH = - 0.63125 × 25

                                     = -15.78 KJ

Thus from the above conclusion we can say that ΔH = -15.78 KJ when 25.0 g of S₈ reacts.

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

#SPJ4

4 0
2 years ago
During soldering, a mixture of metals ('solder') is heated until it melts. The molten metal falls into the gaps between two piec
Pavlova-9 [17]

Answer:

31^oC

Explanation:

Range = Highest value - Lowest value

A 'soft solder' melts between 183 °C and 212 °C.

Melting range of a 'soft solder' = 212-183=29^oC

A 'hard solder' melts between 620 °C and 680 °C.

Melting range of a 'hard solder' = 680-620=60^oC

So,

Difference in melting ranges = Melting range of a 'hard solder'  - Melting range of a 'soft solder' = 60^oC-29^oC=31^oC

4 0
3 years ago
Which choice explains a use of a Venn diagram?
algol13

Answer:

illustrates ways things are similar and different

Explanation:

5 0
3 years ago
Read 2 more answers
Why is oxygen an element ? a it is essential to life b it burn c it combines with hydrogen d it cannot be broken down into a sim
MrRa [10]
D.) It cannot be broken down into a simple substance through chemical means...
5 0
3 years ago
Read 2 more answers
A 3.96x10^-24 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000-cm cuvet; a blank solution containi
viktelen [127]

Actual question from source:-

A 3.96x10-4 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000 cm cuvette.  A blank had an absorbance of 0.029.  The absorbance of an unknown solution of compound A was 0.375.  Find the concentration of A in the unknown.

Answer:

Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}

Explanation:

According to the Lambert's Beer law:-

A=\epsilon l c

Where, A is the absorbance

 l is the path length  

\epsilon is the molar absorptivity

c is the concentration.  

Given that:-

c = 3.96\times 10^{-4}\ M

Path length = 1.000 cm

Absorbance observed = 0.624

Absorbance blank = 0.029

A = 0.624 - 0.029 = 0.595

So, applying the values in the Lambert Beer's law as shown below:-

0.595=\epsilon\times 1.000\ cm\times 3.96\times 10^{-4}\ M

\epsilon=\frac{0.595}{3.96\times 10^{-4}}\ {Ms}^{-1}=1502.53\ {Ms}^{-1}

<u>Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}</u>

4 0
4 years ago
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