3 years ago

The diameter of a round rug is 42 inches. What is the approximate area of the rug?

Mathematics

1 answer:

aksik [14]3 years ago

3 0

Answer:

D, It would be 1,385 Square Inches

Step-by-step explanation:

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You draw one card from a 52 card deck then the card is replaced and the deck the deck is shuffled and your draw again find a the

pashok25 [27]

Answer:1/52

Step-by-step explanation:

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3 years ago

Change your money from dollars to british pounds.you got 560 pounds for 800 dollars.how many pounds will you get for 300 dollars

Anettt [7]

You do a proportion so 560x300=168,000 so then you take 168,000 and divide by 800 so the answer is 210 you would have 210 British pounds for 300 dollars

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3 years ago

Find an example of a 2 dimensional object in your house that is rectangular or triangular.

Dmitry_Shevchenko [17]

Answer:

A = 216 cm^2

P = 80 cm

Step-by-step explanation:

l = 12

w = 18

As the object is rectangular, the area is height * width and the perimeter is

2(height + width) as there are two of each side.

12 * 18 = 216 U^2 U = unit of measurement, I would presume for a poster you use cm so its 216 cm^2

12 + 18 = 40

40 * 2 = 80 cm

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3 years ago

What is the difference between the areas of a circular target region with radius 5 m and a target region with radius 7 m? Round

Oliga [24]

That would be 7²π-5²π=49π-25π=24π≈75

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3 years ago

Read 2 more answers

Write a polynomial that represents the length of the rectangle<br><br> help please !!

disa [49]

Answer:

$\textsf{Length}=0.8x^2-0.7x+0.7\quad \sf units$

Step-by-step explanation:

Area of a rectangle = width × length

Therefore, to find the length of the rectangle, we need to divide the area by the width.

Using long division:

$\large\begin{array}{r}0.8x^2-0.7x+0.7\phantom{)} \\x+0.5{\overline{\smash{\big)}\,0.8x^3-0.3x^2+0.35x+0.35\phantom{)}}}\\-~\phantom{(}\underline{(0.8x^3+0.4x^2)\phantom{-b))))))))))))))}}\\0-0.7x^2+0.35x+0.35\phantom{)}\\ \underline{-~\phantom{()}(-0.7x^2-0.35x)\phantom{-b)))))}}\\ 0.7x+0.35\phantom{)}\\\underline{-~\phantom{()}(0.7x-0.35)}\\ 0\phantom{)}\end{array}$

Therefore, the <u>length</u> of the rectangle is:

$0.8x^2-0.7x+0.7$

5 0

2 years ago