All categories

2 years ago

Angle K measures 67º and angle L measures 119°.

Mathematics

2 answers:

DaniilM [7]2 years ago

5 0

Answer:

C. m Angle M = 113o and m Angle N = 61o

Step-by-step explanation:

It's the only answer that makes all the angles added together equal 360 degrees.

67 + 119 + 113 + 61 = 360

ira [324]2 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Name the angle in 4 ways.

Vaselesa [24]

Angle ABC
ANGLE CBA
ANGLE A
ANGLE B

5 0

2 years ago

Which expressions are equivalent to 8(-10x+3.5y-7)? Select two options.

Novosadov [1.4K]

It should be number 2

5 0

3 years ago

Read 2 more answers

Write words to match the expression 3+(4×12)

Airida [17]

3 more than the produce of 12 and 4.

3 0

3 years ago

Read 2 more answers

A clothing store buys jeans for $12 and marks them up %200 before selling them to customers. What is the selling price of jeans?

zaharov [31]

I would multiply $12 times 200%

5 0

2 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

2 years ago