All categories

3 years ago

How many dots go around Rubidium in a Lewis Dot Structure?

Chemistry

1 answer:

masha68 [24]3 years ago

6 0

Answer:

I believe it's one dot in an electron dot diagram (or rubidium)

Explanation:

I hope this helps

You might be interested in

What is the wavelength of infrared radiation with a frequency of 3.85 x 10^12 Hz?

ELEN [110]

Answer:

Wavelenght is 7,79x10⁻⁵ m

Explanation:

The equation that connects wavelentgh (λ) and frequency (ν) is:

λ=c/ν

Where c is speed of light (3x10⁸ m/sec) and λ is expressed in lenght´s units and ν is expressed in "time⁻¹ " units (for example, sec⁻¹)

According to the details, if we just replace the given value of frequency, we just obtaing wavelenght data:

λ= (3x10⁸ m/sec)/(3,85x10¹² sec⁻¹) = 7,79x10⁻⁵ m

3 0

4 years ago

Question 16 (0.4 points) For the isotope copper-62, what is the number of electrons?

cupoosta [38]

Answer:

Kkkkkkkkkkkkkkk=√π67444

Explanation:

answer=727273737364644464646463636366363+929292929292929339939393

3 0

3 years ago

How to Convert 2.00 miles to fathoms?

k0ka [10]

Answer:

1,760

Explanation:

There are 880 fathoms in a mile. To convert miles to fathoms, multiply the mile value by 880.

So, 2.00 × 880 = 1,760

7 0

4 years ago

What is another name for the representives elements?

Art [367]

Representative elements are also known as Group A elements.

7 0

3 years ago

Calculate the mass of nitric acid required to make a 250mL solution with 2.40 ph

meriva

The mass of nitric acid required to make the given solution is 0.0627 g.

The given parameters:

Volume of the acid, V = 250 mL
pH of the acid, = 2.4

The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;

$H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 0.00398$

The molarity of the nitric acid is calculated as follows;

$= 0.00398 \ H^+ \times \frac{1 \ M \ HNO_3}{1 \ H^+} \\\\= 0.00398 \ M$

The number of moles of the nitric acid is calculated as follows;

$moles = M\times L\\\\moles = 0.00398\ M \ \times \ \frac{250 \ mL}{1000} \\\\moles = 9.95 \times 10^{-4} \ mol.$

The molar mass of nitric acid is calculated as;

$HNO_3 = (1) \ + (14) \ + (16 \times 3) = 63 \ g/mol$

The mass of the nitric acid contained in the calculated number of moles is calculated as;

$mass = moles\ \times \ molar \ mass\\\\mass = 9.95\times 10^{-4} \ mol. \ \times \ 63 \ g/mol\\\\mass = 0.0627 \ g$

Thus, the mass of nitric acid required to make the given solution is 0.0627 g.

Learn more about molarity of acids here: brainly.com/question/13864682

3 0

2 years ago