Answer and Step-by-step explanation:
Solution:
Given:
Let A is the event of a person over 50 diagnosed by health service.
B1 is the event that an adult over 50 actually has diabetes.
B2 is the event that an adult over 50 does not have diabetes.
P (B1) = 8% = 0.08
And P (B2) = 1 – P (B1)
= 1 – 0.08
= 0.92
Correctly diagnose of all persons with diabetes= 95%
P (A/B1) = 0.95
Incorrectly diagnose of all persons without diabetes= 2%
P (A/B2) = 0.02
(a) ) the community health service will diagnose an adult over 50 as having diabetes.
P (B1) P (A/B1) = (0.08) (0.95) = 0.076
P (B2) p (A/B2) = (0.92) (0.02) =0.0184
P (B1) P (A/B1) + P (B2) p (A/B2) = 0.076 + 0.0184
= 0.0944
(b) A person over 50 diagnosed by the health service as having diabetes actually has the disease.
By using formula:
P (B1/A) = P (B1) P (A/B1) / P (B1) P(A/B1) + P (B2) P (A/B2)
Put all the given values:
= (0.08) (0.95) / (0.08) (0.95) + (0.92) (0.02)
=0.076 / 0.076 + 0.0184
=0.076 / 0.0944
= 0.8050
Answer:
-2+3=1
Step-by-step explanation:
AB is 10 units long, so a ratio of 2:3 translates to 4:6 in units.
4 units ahead of A is 4+4 = 8
The answer is (8, 1)
W+1/9 = 5
W = 5-1/9
= [(5*9)-1]/9
= [45-1]/9
= 44/9
Answer:
Widow's Share = Rs 500.05
Son's share = Rs 1400.14
Step-by-step explanation:
Property = 4000.40
Widow get share = 0.125
So, Share of Widow = 0.125 * 4000.40
Widow's Share = Rs 500.05
Remaining Property = 4000.40 - 500.05
Remaining Property = 3500.35
Son's share = 0.4 * 3500.35
Son's share = Rs 1400.14
