Remark
This is like using the distributive principle only you are going backwards. Instead of trying to remove brackets, you are trying to create them.
Solution
Since you want to take - 6 outside the brackets you should divide both terms by - 6
<em><u>- 18a</u></em>: - 18a/- 6 = 3a which is left inside the brackets.
<em><u>-30:</u></em> - 30/-6 = 5
- 6(3a + 5)
Answer
-6(3a + 5)
Answer:
Do you have a graph or a picture tagged along with the question
Step-by-step explanation:
Graph to solve?
There are 5 counts in half a second
Answer:
The answer is actully the third one
Step-by-step explanation:
Divide 1 7/10 by 3/5 to see if the quotient is greater than 2. If it's not, you can't get 2 scarves out of it. If it is, then you can get 2 scarves out of it and have whatever the remainder is as left-over. Before we divide, let's change that 1 7/10 into an improper fraction since it will be easier to work with.
1 7/10 = 17/10
Now we can divide:
The rule for dividing fractions is that you bring up the lower fraction and flip it to multiply, so that looks like this:
×
To simplify before we multiply, we can reduce between the 5 and the 10 and have smaller numbers to deal with:
×
The product there is
So the answer you want from your choices is
"Yes, because the quotient of Fraction 1 and 7 over 10 [division sign]Fraction 3 over 5 is 2 and 5 over 6", third choice
Answer:
Step-by-step explanation:
<u>Given</u>:
AC + CB = 33
CB = 2AC
<u>Find</u>:
AC, CB
<u>Solution</u>:
Using substitution, we have ...
AC +2AC = 33
AC = 33/3 = 11
CB = 2·11 = 22
AC = 11 cm; CB = 22 cm.