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artcher [175]
3 years ago
14

Please can y'all help me asp

Mathematics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

/

Step-by-step explanation:

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Each leg of a 45°-45°-90° triangle measures<br> 14 cm. What is the length of the hypotenuse?
4vir4ik [10]

For a 45-45-90 angle the hypotenuse is s * square root of 2

so the hypotenuse is 14 * square root of 2 or 19.8

:)))

6 0
3 years ago
Read 2 more answers
E. solve for y<br>-3y+6​
Rudik [331]

Answer:

y = 2

Step-by-step explanation:

-3y + 6 = 0

-3y = -6

y = -6/-3

y = 6/3

y = 2

6 0
3 years ago
Read 2 more answers
Which two ratios form a proportion?
s2008m [1.1K]

Answer:

02:3 and 12:18

Step-by-step explanation:

A proportion is formed when the larger ratio can be simplified to equal the smaller ratio:

#1

02:3 and 4:12

Reducing the larger ratio: 4:12=1:3

Hence, not a proportion.

#2

02:3 and 6:12

Reducing the larger ratio: 6:12=1:2

Hence, not a proportion.

#3

02:3 and 12:18

Reducing the larger ratio: 12:18=2:3

Hence, they form a proportion.

#4

02:3 and 12:18

Reducing the larger ratio: 12:36=1:3

Hence, not a proportion.

4 0
3 years ago
How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title
kotegsom [21]
Let t=\sqrt y, so that t^2=y, t^4=y^2, and \mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}. Then

\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}

Now let y=\sqrt2\tan z, so that \mathrm dy=\sqrt2\sec^2z\,\mathrm dz. Then

\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C

Transform back to y to get

\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C

and again to get back a result in terms of t.

\dfrac1{2\sqrt2}\arctan\left(\dfrac{t^2}{\sqrt2}\right)+C
3 0
3 years ago
- The position of an object moving in a straight line
Misha Larkins [42]

Answer:

s(t) = 2t^2-3t

19 = 2t^2-3t

2t^2-3t-19=0

t = [3 +- sqrt(9-4*2*-19)]/4

t = [3 +- sqrt(161)]/4

t = [3 +- 12.6886]/4

Positive answer:

t = [3+12.6886]/4

t = 3.9221 seconds

Step-by-step explanation:

4 0
3 years ago
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