Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
i cant tell you that it is from a test
for 1st
use the formula of inlargement
A(x,y)when enlarging by scale factor k gives A'(kx,ky)
for 2nd
a=
(2a+3)-(a-5)(2a+2)+a^2
b=
3y(7y-8)
f(x) = mx + b
m = slope = -5
f(2) = 10 = (-5)(2) + b
b = 10 + 10 = 20
Ans. m=-5, b = 20
Answer:
A. 4.1
Step-by-step explanation:
3+4+ 5+ 3+ 4+ 5+ 6+ 7+ 1+ 2+ 3+ 4+ 5+ 6+ 4+ 8+ 4+ 3+ 2= 79
79/ 19 = 4.1
