Answer: yes, because it is a straight line and is on the origin and goes through the origin so it is a proportional relationship
hoped this helped let me know if it did
It is 8x-5 you replace the variable y with 3 in the expression
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Hope this helps :) (the first circle is a fraction of thirds and the second circle is a fraction of sixths)
The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9
<h3>How to determine the quadratic equation?</h3>
From the question, the given parameters are:
Roots = (-1 - √2)/3 and (-1 + √2)/3
The quadratic equation is then calculated as
f(x) = The products of (x - roots)
Substitute the known values in the above equation
So, we have the following equation

This gives

Evaluate the products

Evaluate the like terms

So, we have
f(x) = x²+ 2/3x - 1/9
Read more about quadratic equations at
brainly.com/question/1214333
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