All categories

3 years ago

A point is located in quadrant II of a

Mathematics

1 answer:

givi [52]3 years ago

3 0

Answer:

Choose a point with a negative x coordinate and a positive y coordinate.

Step-by-step explanation:

The quadrants are labeled counter clockwise 1, 2, 3, and 4.

Quadrant I - has x and y coordinate both positive.

Quadrant 2 - has x coordinate negative and y coordinates positive.

Quadrant 3 - has x and y coordinates both negative.

Quadrant 4 - has x coordinates positive and y coordinates negative.

Since the point is in quadrant 2, choose a point where x is negative but y is positive like (-3, 2).

You might be interested in

Classify each of the sentences below as an atomic statement, a molecular statement, or not a statement at all. If the statement

MArishka [77]

Answer:

a. The sum of the first 100 odd positive integers - Not a statement

b. Everybody needs somebody sometime - Atomic statement

c. The Broncos will win the Super Bowl or I'll eat my hat - Molecular statement (disjunction)

d. We can have donuts for dinner, but only if it rains - Molecular statement (conditional)

e. Every natural number greater than 1 is either prime or composite - Atomic statement

f. This sentence is false - Not a statement

Step-by-step explanation:

A statement in mathematics can be said to be any declarative statement that can either be true or false. While a sentence is considered to not be a statement if

Statements are divided into 2:

Atomic statements: These are statements that cannot be split into mini statements.
Molecular statements: These are the opposites of atomic statements. They are statements that cannot be spilt. This can further be divided into; conjunction, disjunction, conditional, bi-conditional and negation

3 0

3 years ago

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

3 years ago

The object below was made by placing a cone on top of a cylinder. The base of the cone is congruent to the base of the cylinder.

Ber [7]

Answer:

Part 1) The volume of the object is $32\pi\ cm^{3}$ or $100.48\ cm^{3}$

Part 2) see the procedure

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) What is the volume, in cubic centimeters, of the object?

we know that

The volume of the object is equal to the volume of the cylinder plus the volume of the cone

Find the volume of the cone

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2} h$

we have

$r=4/2=2\ cm$ -----> the radius is half the diameter

$h=3\ cm$

substitute the values

$V=\frac{1}{3}\pi (2^{2})(3)=4\pi\ cm^{3}$

Find the volume of the cylinder

The volume of the cylinder is equal to

$V=\pi r^{2} h$

we have

$r=4/2=2\ cm$ -----> the radius is half the diameter

$h=(10-3)=7\ cm$

substitute the values

$V=\pi (2^{2})(7)=28\pi\ cm^{3}$

Part 2) Then explain how you found the volume of the total shape

The volume of the total shape is equal to the volume of the cylinder plus the volume of the cone

$4\pi\ cm^{3}+28\pi\ cm^{3}=32\pi\ cm^{3}$ ------> exact value

Find the approximate value of the volume

assume

$\pi=3.14$

$32(3.14)=100.48\ cm^{3}$

7 0

3 years ago

Read 2 more answers

Could you please explain it?

Troyanec [42]

Hello,
there are some words that I could not read. But:
I support evements are independants.
p(s)=0.2
p(l)=1-0.2=0.8 l=lose

1)0.8*0.2=0.16

2) 0.8²*0.2=0.128

3) 0.8^3*0.2=0.1024

4) 0.2*0.8^(n-1)

6 0

3 years ago

The Ideal selling price for a certain car is $26,000. The make a good deal app indicates that local prices could vary by 6 perce

Ivenika [448]

Answer:

($26,000/100)*94 = $24,440

Step-by-step explanation:

Divide 26,000 by 100 and multyply by 94 (100% - 6%) = $24,440

3 0

2 years ago