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3 years ago

A point is located in quadrant II of a

Mathematics

1 answer:

givi [52]3 years ago

3 0

Answer:

Choose a point with a negative x coordinate and a positive y coordinate.

Step-by-step explanation:

The quadrants are labeled counter clockwise 1, 2, 3, and 4.

Quadrant I - has x and y coordinate both positive.

Quadrant 2 - has x coordinate negative and y coordinates positive.

Quadrant 3 - has x and y coordinates both negative.

Quadrant 4 - has x coordinates positive and y coordinates negative.

Since the point is in quadrant 2, choose a point where x is negative but y is positive like (-3, 2).

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If f(x)=3x-1 and g(x)=x+2,find (f-g)(x)

oksian1 [2.3K]

Answer:

$\large\boxed{(f-g)(x)=2x-3}$

Step-by-step explanation:

$(f-g)(x)=f(x)-g(x)\\\\f(x)=3x-1,\ g(x)=x+2\\\\\text{substitute:}\\\\(f-g)(x)=(3x-1)-(x+2)\\\\=3x-1-x-2\qquad\text{combine like terms}\\\\=(3x-x)+(-1-2)\\\\=2x-3$

7 0

3 years ago

Help pls need answer asap

Varvara68 [4.7K]

Answer:

Carl traveled 281.25 km by bus and 1,618.75 km by plane.

Step-by-step explanation: v1 = 60 km/h average speed by bus to Toronto

v2 = 700 km/h average speed by plane to Winnipeg

d = 1,900 km the total distance traveled

t = 7 h total traveling time

t1 = the time of the travel by bug

t2 = the time of the travel by plane

t = t1 + t2 the total time

d1 = the distance traveled by bus

d2 = the distance traveled by plane

d = d1 + d2 the total distance

Since average speed = distance/time we have time = distance/avg.speed

t1 = d1/v1 that is t1 = d1/60

t2 = d2/v2 that is t2 = d2/700

Plug the above values into t1 + t2 = t.

We have the following system of equations:

d1/60 + d2/700 = 7

d1 + d2 = 1900

.......

Click here to see the step by step solution for 'd1' and 'd2'

.......

d1 = 281.25 km

d2 = 1,618.75 km

Carl traveled 281.25 km by bus and 1,618.75 km by plane.

7 0

2 years ago

Help me please brainly

3241004551 [841]

Step-by-step explanation:

3x+3

10+2x

8x+24

8a+8b+8c

6 0

3 years ago

Given parallelogram ABCD , diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8 . Find the length of AC

Crank

Answer:

I think the answer shod be B

3 0

3 years ago

In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel

Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

Now,

change in sulfur oxide with time i.e $\frac{\textup{dS}}{\textup{dt}}$

differentiating the given relation with respect to time 't'

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = $2\times110P\frac{\textup{dP}}{\textup{dt}}$ + 20

at P = 100 and $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = 2 × 110 × 100 × 10 + 20

$2S\frac{\textup{dS}}{\textup{dt}}$ = 220020

$\frac{\textup{dS}}{\textup{dt}}$ = $\frac{\textup{220020}}{\textup{2S}}$

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

8 0

3 years ago