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Roman55 [17]
3 years ago
15

A cylinder of oxygen gas has a volume of 10.0 liters at 7.66 atm and 27.0oC. The cylinder is heated until the pressure is 428 kP

a and the volume reaches 30.0 liters. What is the new temperature of the cylinder?
Chemistry
1 answer:
iris [78.8K]3 years ago
6 0

Answer:

Explanation:

428 x 10³ Pa = 4.28 x 10⁵ Pa = 4.28 atm

We shall use the gas equation

P₁V₁ / T₁ = P₂V₂ / T₂

7.66  x 10 / ( 273 + 27 ) = 4.28 x 30 / T₂

.255 = 128.4 / T₂

T₂ = 503.53

= 503.53 - 273 = 230.53⁰C .

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