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2 years ago

The second reaction in the formation of sulfuric acid occurs slowly.

Chemistry

1 answer:

rjkz [21]2 years ago

5 0

Answer: The correct option is $NO_2(g)$

Explanation:

A catalyst is defined as the chemical species that increases the reaction rate but does not participate in it and is left behind after the completion.

A homogeneous catalyst is one that is present in the same phase as the reactants and products.

A heterogeneous catalyst is one that is present in different phase as that of reactants and products.

For the given chemical reaction:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

As all the reactants and products are in gaseous state so, the homogeneous catalyst must also be in the gaseous state only.

Hence, the correct option is $NO_2(g)$

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Type the correct answer in the box. Express your answer to two significant figures. An industrial vat contains 650 grams of soli

nikklg [1K]

88.98 %

The Balance Chemical Equation is as follow,

2 HCl + Pb(NO₃)₂ → 2 HNO₃ + PbCl₂

According to equation,

331.2 g (1 mole) Pb(NO₃)₂ produces = 278.1 g (1 mole) PbCl₂

So,

870 g of Pb(NO₃)₂ will produce = X g of PbCl₂

Solving for X,

X = (870 g × 278.1 g) ÷ 331.2 g

X = 730.5 g of PbCl₂

Therefore,

Theoretical Yield = 730.5 g

Also as given,

Actual Yield = 650 g

So using following formula for percentage yield,

%age Yield = (Actual Yield / Theoretical Yield) × 100

Putting values,

%age Yield = (650 g / 730.5 g) × 100

%age Yield = 88.98 %

Brianliest please and thank you.

6 0

3 years ago

Please help!!!!!! Name 3 differences between vascular and non vascular plants

Arlecino [84]

Am letting the picture doing the talk.

8 0

2 years ago

the symbol for xenon (xe) would be a part of the noble gas notation for the element antimony. cesium.

trapecia [35]

The symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

For writing the electronic configuration of any element by using the preceding noble gas configuration, we simply use the symbols of noble gas belongs to the previous period of that particular elements. We can't use the symbol of noble gas of same period from which the element belong.

A is the wrong option because the noble gas in the preceding period to the period from which antimony belongs is krypton.

The actual electronic configuration of antimony is as follow:

[Kr] 4d10 5s2 5p3

B is correct option because the noble gas in the preceding period to the period from which Cesium belongs is Xenon.

The actual electronic configuration of Cesium is as follow:

[Xe] 6s1

Thus, we concluded that the symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

learn more about Noble gas:

brainly.com/question/2094768

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8 0

1 year ago

Which is an element? A: H20 B: NaCl C: Mg D: CO

Talja [164]

The answer is option D "CO." Co also known as Cobalt is the 27th element on the periotic table. It was discovered in 1735, it's boiling point is 3200 k.

Atomic mass: 58.9332
Protons: 27
Neutrons: 32
Electrons: 27

Hope this helps!

3 0

2 years ago

Read 2 more answers

Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exert

Damm [24]

Answer: The given statement is true.

Explanation:

According to the Dalton's law, total pressure of a mixture of gases that do not react with each other is equal to the partial pressure exerted by each gas.

The relationship is as follows.

$p_{total} = \sum_{i=1}^{n} p_{i}$

or, $p_{total} = p_{1} + p_{2} + p_{3} + p_{4} + ......... + p_{n}$

where, $p_{1}, p_{2}, p_{3}$ ....... = partial pressure of individual gases present in the mixture

Also, relation between partial pressure and mole fraction is as follows.

$p_{i} = p_{total} \times x_{i}$

where, $x_{i}$ = mole fraction

Thus, we can conclude that the statement Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exerted independently by each gas in the mixture, is true.

5 0

2 years ago