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german
3 years ago
15

The second reaction in the formation of sulfuric acid occurs slowly.

Chemistry
1 answer:
rjkz [21]3 years ago
5 0

<u>Answer:</u> The correct option is NO_2(g)

<u>Explanation:</u>

A catalyst is defined as the chemical species that increases the reaction rate but does not participate in it and is left behind after the completion.

A homogeneous catalyst is one that is present in the same phase as the reactants and products.

A heterogeneous catalyst is one that is present in different phase as that of reactants and products.

For the given chemical reaction:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

As all the reactants and products are in gaseous state so, the homogeneous catalyst must also be in the gaseous state only.

Hence, the correct option is NO_2(g)

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Please help very urgent well mark brainiest no need for expiation ether just need answer please
koban [17]

Answer: c hope this helps

7 0
3 years ago
Why were more than 2 total atoms needed to create this compound?
Ksivusya [100]

Answer:

Compound is like a community and needed more than 2 atoms.

Explanation:

1 atom

2 atoms= 1 molecule

3 atoms (either of same or different elements)= compound

4 0
4 years ago
From Young's experiment, how does the frequency of light affect the number of lines observed?
Marina CMI [18]

Answer : (C) "Higher frequencies have larger spaces between lines".

Explanation:

In Young's experiment, the condition for constructive interference is given by :

dsin\theta=n\lambda.........(1)

n is order or number of lines observed

d is distance between slits

\theta is the angle between the path and the line from screen to the slits.

We also know that, c=\nu \lambda

or

\lambda=\dfrac{c}{\nu}

where,

c is the speed of light

\nu is frequency

\lambda is wavelength

So, equation (1) turns into

dsin\theta=n\dfrac{c}{\nu}

\nu=\dfrac{n\ c}{d\ sin\theta}

So,

\nu\propto n

or

Higher frequencies have larger spaces between line.

So, correct option is (C).

3 0
3 years ago
Read 2 more answers
What is e cell (in units of volts) for a galvanic cell constructed from barium and manganese electrodes?
gulaghasi [49]

Main Answer: The standard electrode potential of galvanic cell constructed from barium and manganese electrode is 4.097.

Explanation:

When the galvanic cell constructed between Manganese and Barium, the half reactions will be as follows:

Mn2+(aq) + 2e-⟶ Mn(s)                                             E1 = −1.185

Ba2+(aq) + 2e-⟶ Ba(s)                                                 E2 = −2.912

By considering the above two reactions, the standard electrode potential can be calculated.

The galvanic cell standard electrode potential is given by E1 + E2 = 1.185 + 2.912 = 4.097 volts

What is standard electrode potential?

Standard electrode potential is defined as the measure of reducing power of any compound or element. Its units are volts.

To know more about galvanic cell, please visit:

brainly.com/question/13031093

#SPJ4

3 0
2 years ago
If 8.0 g of sulfur dioxide came in contact with a cloud containing 2.2 g of oxygen, indicate the
Inga [223]

Answer:

Limiting reactant= SO₂, Theoretical yield = 9.6g SO₃

Explanation:

The first step is is to find the limiting reactant; you do this using stoichiometry.

The reactant that produces the smallest amount of sulfur trioxide SO₃, is the limiting reactant.

In this problem, SO₂ is the limiting reactant.

Now to find the theoretical yield we will use the smallest value of SO₃.

I have uploaded a picture to better illustrate the problem and hope it helps.

5 0
3 years ago
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