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zaharov [31]
3 years ago
11

Problem page an electron in an atom is known to be in a state with magnetic quantum number =ml−2 . what is the smallest possible

value of the principal quantum number n of the state?
Chemistry
2 answers:
vovikov84 [41]3 years ago
6 0

<em>n</em> = 3. The principal quantum number must be at least 3 to have a magnetic quantum number <em>ml</em> = -2

The rules are:

• <em>n</em> > 0

• <em>l </em>< <em>n</em>

• |<em>ml</em>| ≤ <em>l </em>

Thus, if <em>ml</em> = -2, <em>l</em> ≥ 2.

If <em>l </em>≥ 2 and n ><em> l</em>, the allowed values of <em>n</em> are 3, 4, 5, etc.

The smallest allowed value of <em>n</em> is <em>n</em>  = 3<em>. </em>

vfiekz [6]3 years ago
5 0

Answer:

n=3

Explanation:

Hello,

Magnetic number accounts for the energy levels of electrons within the subshells, in such a way, if ml=2 or -2, we realize that such atom has five subshells, -2,-1,0,1,2 (magnetic number equal to 2) which are contained into the third shell, this is n=3.

This is known due to the fact that the first shell has the subshell 0 and the second shell the subshells -1,0,1.

Best regards.

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4 0
2 years ago
Starting with 250 mL of a 0.250 M solution of HBr; a) Calculate the initial pH of the solution.b) Calculate the pH after adding
maxonik [38]

Answer:

a.

pH =  0.602

b.

pH = 1.5

c.

pH = 7

d.

pH = 12.1

Explanation:

a ) To calculate the pH, use the following equation:

pH = -log [H+]

Hbr is a strong acid, so the [H+] concentration can be calculated as follow:

[HBr] = 0.250 M

As acid Hbr:

Hbr = H+ + Br-

As strong acid HBr dissociates at all, so

[HBr] = [H+] = 0.250 M

So the pH:

<u>pH = -log [0.250 M] = 0.602</u>

<u></u>

<u>b) Calculate the pH after adding 250 mL of 0.125M NaOH</u>

<u></u>

<u>I</u>n this point, the reactions starts:

<u></u>

HBr + NaOH = H2O + NaBr

- First, we gonna find the mol of each reactant:

HBr:

mol = [M] × L

mol = 0.250 M × 0.250 L

mol = 0.0625 mol HBr

NaOH:

mol = [M] × L

mol = 0.125 M × 0.250L

mol = 0.03125 mol NaOH

In base on the reaction, it’s needed 1 mol of NaOH to neutralize 1 mole of HBr, so to neutralize 0.0625 moles of HBr its needed 0.0625 mol of NaOH:

0.0625 mol HBr – 0.03125 mol HBr = 0.03125 mol HBr

These are the moles free in the solution, and we going to use them to calculate the pH:

pH = -log [ H]

pH = - log [ 0.03125 ] = 1.5

<u>c) Calculate the pH after adding 500 mL of 0.125M NaOH</u>

NaOH:

mol = [M] × L

mol = 0.125 M × 0.500L

mol = 0.0625 mol NaOH

In base on the reaction, it’s needed 1 mol of NaOH to neutralize 1 mole of HBr, so to neutralize 0.0625 moles of HBr its needed 0.0625 mol of NaOH:

0.0625 mol HBr – 0.0625 mol HBr = 0 HBr

pH = 7

<u>d) Calculate the pH after adding 600 mL of 0.125M NaOH.</u>

<u>NaOH:</u>

mol = [M] × L

mol = 0.125 M × 0.600L

mol = 0.075 mol NaOH

In base on the reaction, it’s needed 1 mol of NaOH to neutralize 1 mole of HBr, so to neutralize 0.0625 moles of HBr its needed 0.0625 mol of NaOH:

0.075 mol NaOH – 0.0625 mol NaOH = 00125 NaOH

These are the moles free in the solution, and we going to use them to calculate the pH:

pOH = -log [ OH]

pOH = - log [ 0.0125 ] = 1.90

pH + pOH = 14

pH = 14- pOH = 14 – 1.90 = 12.1

4 0
3 years ago
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