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3 years ago

3. What is the substance ozone?

1 answer:

8 0

Chlorofluorocarbons and other halogenated ozone depleting substances are mainly responsible for man made chemical ozone depletion.

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Data can be arranged in visual displays is called graphs to make identifying Trends easier.

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3 years ago

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What type of forces affects the speed and direction of motion of an object?

kirill115 [55]

I am pretty sure the correct answer is B.
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4 years ago

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How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O? The reaction is:

Readme [11.4K]

Answer:

There is 5.72 grams of H2 formed

1) C+ H2O → CO + H2

2) We start with 34 grams of carbon that will react with an excess of H2O

3) 5.72 grams of H2

Explanation:

Step 1: Data given

Mass of carbon = 34.00 grams

H2O is in excess

Molar mass of C = 12 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

C+ H2O → CO + H2

Step 3: What is the starting substance

We start with 34 grams of carbon that will react with an excess of H2O

Step 4: Calculate moles carbon

Moles C = mass C / molar mass C

Moles C = 34.00 grams / 12.00 g/mol

Moles C = 2.833 moles

Step 5: Calculate moles H2

Carbon is the limiting reactant.

For 1 mol Carbon we need 1 mol H20 to produce 1 mol CO and 1 mol H2

For 2.833 moles C we'll have 2.833 moles H2

Step 6: Calculate mass of H2

Mass H2 = moles H2 * molar mass H2

Mass H2 = 2.833 moles * 2.02 g/mol

Mass H2 = 5.72 grams of H2

8 0

4 years ago

In the following reaction 8 grams of ethane are burned and 11 grams of CO2 are collected. What is the percent yield? 2C2H6+7O2=

Alika [10]

47% yield.
First, let's determine how many moles of ethane was used and how many moles of CO2 produced. Start with the respective atomic weights.
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass C2H6 = 2 * 12.0107 + 6 * 1.00794 = 30.06904 g/mol
Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087 g/mol
Moles C2H6 = 8 g / 30.06904 g/mol = 0.266054387 mol
Moles CO2 = 11 g / 44.0087 g/mol = 0.249950578 mol
Looking at the balanced equation, for every 2 moles of C2H6 consumed, 4 moles of CO2 should be produced. So at 100% yield, we should have 0.266054387 / 2 * 4 = 0.532108774 moles of CO2. But we only have 0.249950578 moles, or 0.249950578 / 0.532108774 = 0.46973587 =
46.973587% of what was expected.
Rounding to 2 significant figures gives 47% yield.

8 0

4 years ago

PLLLLEEAASEEE HELLPP!!

nekit [7.7K]

<u>Answer:</u> The correct option is C) 1.68 mol/L

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (L)}}$ .....(1)

Given values:

Given mass of $C_6H_{12}O_6$ = 150 g

Molar mass of $C_6H_{12}O_6$ = 180 g/mol

Volume of the solution = 0.50 L

Putting values in equation 1, we get:

$\text{Molarity of solution}=\frac{150}{180\times 0.50}\\\\\text{Molarity of solution}=1.68M$

Hence, the correct option is C) 1.68 mol/L

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3 years ago