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Pavlova-9 [17]
2 years ago
5

3. What is the substance ozone?

Chemistry
1 answer:
Reptile [31]2 years ago
8 0
Chlorofluorocarbons and other halogenated ozone depleting substances are mainly responsible for man made chemical ozone depletion.
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How do the bonds differ in<br> each type?
VashaNatasha [74]

Answer:

Bonds basically differs with each other due to sharing of electrons .

Explanation:

There are majorly three kinds of bonds

1. Ionic bonds which forms due to an element donate an electron to another element completely .

2. covalent bonds which forms with the mutual sharing of electrons b/w two atoms .

3. metallic bonds which forms b/w metals & they share electrons due to electron negativity difference b/w two atoms or elements

7 0
2 years ago
Read 2 more answers
Which radiation can only be stopped by thick layers of dense metal? (2 points)
AfilCa [17]
Gamma rays have the highest penetrating power so it can only be stopped by thick layers of dense metal. :)
5 0
3 years ago
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Can someone please help me with my chem final!!
scoundrel [369]

Answer:

direct

Explanation:

the more dense it is the more pressure it will exert

6 0
2 years ago
(a) The original value of the reaction quotient, Qc, for the reaction of H2(g) and I2(g) to form HI(g) (before any reactions tak
Taya2010 [7]

Answer:

Here's what I get  

Explanation:

Assume the initial concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.

We must calculate the initial concentration of HI.

1. We will need a chemical equation with concentrations, so let's gather all the information in one place.

                   H₂ +    I₂    ⇌ 2HI

I/mol·L⁻¹:    0.30   0.15         x

2. Calculate the concentration of HI

Q_{\text{c}} = \dfrac{\text{[HI]}^{2}} {\text{[H$_{2}$][I$_{2}$]}} =\dfrac{x^{2}}{0.30 \times 0.15} =  5.56\\\\x^{2} = 0.30 \times 0.15 \times 5.56 = 0.250\\x = \sqrt{0.250} = \textbf{0.50 mol/L}\\\text{The initial concentration of HI is $\large \boxed{\textbf{0.50 mol/L}}$}

3. Plot the initial points

The graph below shows the initial concentrations plotted on the vertical axis.

 

7 0
3 years ago
What is the molar concentration of hydronium ions in a sample of a soft drink that has a ph of 4?
hammer [34]

[H^{+}] value of soft drink is 0.0001mol/l when given pH is 4.

Given:

pH = 4

Needs to find: [H^{+}]

Formula to find: pH=−log_{10} [H^{+}]

We can put the values of pH in above formula as,

pH=−log_{10} [H^{+}]

4 =−log_{10} [H^{+}]

To calculate hydonium ion concentration, formula is as follows;

[H^{+}] = 10^{-pH}

[H^{+}] = 10^{-4} = 0.0001mol/l

[H^{+}] value of soft drink is 0.0001mol/l

Learn more about pH here:

brainly.com/question/2288405

#SPJ4

6 0
1 year ago
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