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Pavlova-9 [17]
3 years ago
5

3. What is the substance ozone?

Chemistry
1 answer:
Reptile [31]3 years ago
8 0
Chlorofluorocarbons and other halogenated ozone depleting substances are mainly responsible for man made chemical ozone depletion.
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Magnesium hydroxide reacts with hydrogen chloride, a double-displacement reaction occurs and produces magnesium chloride and wat
Natalija [7]

Explanation:

magnesium Hydroxide + Hydrochloric react together and give us magnesium chloride + water

5 0
2 years ago
Based on the chemical bonds present in this molecule, we would classify it as a(n)
MrMuchimi

Answer is C – Unsaturated fat.

Fats are large molecules basically made from a combination of glycerol and three chains of fatty acids. Usually fats consist of C, H and O. According to the C – C bond, there are two types of fats as saturated fats and unsaturated fats. Saturated fats have only C – C single bonds and all C atoms are sp³ hybridized atoms. But in unsaturated fats other than C – C single bonds there are C – C double bonds. Hence, both sp³ and sp² hybridized C atoms can be seen.


8 0
3 years ago
Read 2 more answers
How many moles are in 43.9 L of oxygen
Ede4ka [16]

Answer: 2 mol

Explanation:

- According to the ideal gas law, One mole of an ideal gas at STP (standard temperature and normal pressure) occupies 22.4 liters.

- Using cross multiplication,

                               1 mol of (O2)        →       22.4 L

                                       ?                   →        43.9 L

Therefore, the number of moles of oxygen in 43.9 L = (43.9 × 1)/ 22.4 = 1.96 mol≈ 2 mol..


3 0
3 years ago
What is the area of a medium triangle?​
galben [10]

Answer: Area of a Triangle Equals Base x Height / 3

Explanation: Hope this works

6 0
3 years ago
If it takes 5 hours to produce 8.0 kg of alcohol, how any days will it take to consume 1000 kg of glucose?
Ipatiy [6.2K]

It takes 21.3 days

<h3>Further explanation</h3>

Given

5 hr = 8 kg Alcohol

Required

Days to consume 1000 kg of glucose

Solution

Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,

C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂

mol ethanol :

\tt \dfrac{5000~g}{46~g/mol}=108.7~moles

moles of glucose to produce 108.7 moles ethanol :

\tt \dfrac{1}{2}\times 108.7=54.35

54.35 moles = 5 hours

moles of 1000 kg of glucose :

\tt \dfrac{10^6~g}{180~g/mol}=5555.5~moles

So for 5555.5 moles, it takes :

\tt \dfrac{5555.5}{54.35}\times 5~hours=511.085~h=21.3~days

7 0
3 years ago
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