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3 years ago

Pls tell me so quotes of not giving up

Mathematics

1 answer:

lesantik [10]3 years ago

4 0

Answer:

Step-by-step explanation:

Knowledge is knowing a tomato is a fruit, wisdom is not putting it in a fruit salad

Your time is too valuable to waste on those who don't deserve it

Never give up great things take time

Failure is not an acception

As a wise fish once said "Just Keep Swimming" the more u swim the closer you get to your goal.

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At a vehicle dealership 5 cars are sold for 2 trucks. Last year the dealership sold 128 trucks how many cars did they sell?

baherus [9]

The answer should be 64 cars sold at the dealership

7 0

2 years ago

The following data shows the quarterly profit (in thousands of dollars) made by a particular company in the past 3 years.

laiz [17]

Answer:

208.82 ; 61.33

Step-by-step explanation:

Given the data:

Year Quarter Profit ($1000s)

1 1 45

1 2 51

1 3 72

1 4 50

2 1 49

2 2 45

2 3 79

2 4 54

3 1 42

3 2 58

3 3 70

3 4 56

The 3 period moving average :

Yr Qtr Profit ($1000s)Pt ____ Ft ____ e=(PT-Ft)²

1 _ 1 ___45 __

1 _ 2 __ 51 __

1 _ 3 __ 72 __

1 _ 4 __ 50 ______________56 ____ 36

2 _ 1 __ 49 ______________57.67__ 75.17

2 _ 2__ 45 ______________57 ____ 144

2 _ 3__ 79 ______________48 ____961

2 _ 4__ 54 ______________57.67 _ 13.47

3 _ 1__ 42 ______________59.33__300.33

3 _2 __ 58 ______________58.33__ 0.11

3 _ 3__ 70 ______________51.33__ 348.57

3 _ 4 __56 ______________56.67__0.45

MSE = Σ(Pt - Ft)² ÷ n

MSE = (36+75.17+144+961+13.47+300.33+0.11+348.57+0.75) ÷ 9

= 208.82

Forecast for next quarter :

(58 + 70 + 56) / 3 = 184 /3 = 61.33

8 0

3 years ago

The midpoint of FG is (6-4) and the coordinates of point Fare (-3, 6) What are the coordinates of point G?

lora16 [44]

Answer:

(15,-14)

Step-by-step explanation:

Given that,

The midpoint of FG is (6-4) and the corrdinates of F are (-3,6).

Let (x,y) be the coordinates of point G. Using mid point formula,

$\dfrac{x+(-3)}{2}=6\ \text{and}\ \dfrac{y+6}{2}=-4\\\\x-3=12\ \text{and}\ y+6=-8\\\\x=15,\ \text{and}\ y=-14$

So, the coordinates of G are (15,-14).

4 0

3 years ago

The coefficients in the expression of (x+y)^4 are

DENIUS [597]

Answer:

the coefficients are 1,4,6,4,1.

Step-by-step explanation:

I hope this helps

4 0

3 years ago

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$

Inputting the boundary condition, t = a = ∞, t = 0:

$F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

3 0

3 years ago