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umka21 [38]
2 years ago
7

NEED HELP ASAP!!!!!! describe the two different types of solids. in ur own words

Chemistry
1 answer:
Rudiy272 years ago
8 0

Answer:

crystalline and amorphous.

Explanation:

Crystalline solids are the most common type of solid, they are characterized by a regular crystalline organization of atoms that confer a long-range order, Amorphous, or non-crystalline, solids lack the long-range order

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State whether homgenous mixture or heterogenoues mixture soda water
Citrus2011 [14]

Answer: homogeneous

Explanation: The taste of soda water is constant till the end. The carbon dioxide is dissolved homogeneously in soda water.

4 0
3 years ago
How is the density of a substance calculated?
murzikaleks [220]
Example:

sample density of gasoline, 20 g of weigth into 5 <span>mL

Answer:

D = m / V

D = 20 g / 5 mL

D = 4 g/mL</span>
3 0
3 years ago
A piece of material with a mass of 755 g is heated to 84.5 c and added to 50 g of water at 5
lana [24]
Alright sorry you're getting the answer hours later, but i can help with this.
so you're looking for specific heat, the equation for it is <span>macaΔTa = - mbcbΔTb with object a and object b. that's mass of a times specific heat of a times final minus initial temperature of a equals -(mass of b times specific heat of b times final minus initial temperature of b)
</span>so putting in your values is, 755g * ca * (75 celsius - 84.5 celsius) = -(50g * cb * (75 celsius - 5 celsius))
well we know the specific heat of water is always 4180J/kg celsius, so put that in for cb
with a bit of simplification to the equation by doing everything on each side first you have, -7172.5 * ca = -14630000
divide both sides by -7172.5 so you can single out ca and you get, ca= 2039.74
add units for specific heat which are J/kg celsius and the specific heat of the material is 2039.74 J/kg celsius

6 0
3 years ago
choose any bases that will selectively deprotonate the above acid, that is, any bases that will favor the formation of products.
Zanzabum

In order to deprotonate an acid, we must remove protons in order to achieve a more stable conjugate base. For this example, we can use the relationship between carboxylic acid and hydroxide.

Deprotonation is the removal of a proton from a specific type of acid in reaction to its coming into contact with a strong base. The compound formed from this reaction is known as the conjugate base of that acid. The opposite process is also possible and is when a proton is added to a special kind of base. This is a process referred to as protonation, which forms the conjugate acid of that base.

For the example we have chosen to give, the conjugate base is the carboxylate salt. This would be the compound formed by the deprotonated carboxylic acid. The base in question was strong enough to deprotonate the acid due to the greater stability offered as a conjugated base.

To learn more visit:

brainly.com/question/5613072?referrer=searchResults

8 0
2 years ago
Each of the following organs had a role in excretion, EXCEPT for the _____?
eimsori [14]

Answer:

c. the heart

all the rest actually will excrete, the heart is in a closed system so contributes to excretory organs but doesn't actually do it barring an accident

Explanation:

8 0
3 years ago
Read 2 more answers
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