Why should copper and sodium be in different groups

The teacher in item 10 also needs to order plastic tubing. If each of the 60 students need 750 mm of tubing, what length of tubi

Alex777 [14]

45 m. If each student needs 750 mm of tubing, the teacher should order 45 m of tubing.

a) Find the <em>length in millimetres</em>

Length = 60 students x (750 mm tubing/1 student) = 45 000 mm tubing

b) Convert <em>millimetres to metres </em>

Length = 45 000 mm tubing x (1 m tubing/1000 mm tubing) = 45 m tubing

6 0

3 years ago

Does anyone know what the formula would be for Rhenium V Biphosphate?

Georgia [21]

Answer:Re3(PO4)2 I think I'm wrong

Explanation:

8 0

3 years ago

Suppose you start with a solution of red dye #40 that is 2.3 ✕ 10−5 M. If you do three successive volumetric dilutions pipetting

larisa [96]

Answer: Therefore, the concentration of final solution is $4.0\times 10^{-8}M$

Explanation:

According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = $2.3\times 10^{-5}M$

$V_1$ = volume of stock solution = 3.00 ml

$M_2$ = molarity of diluted solution = ?

$V_2$ = volume of diluted solution = 25.00 ml

$2.3\times 10^{-5}M\times 3.00=M_2\times 25.00$

$M_2=0.28\times 10^{-5}M$

Therefore, the concentration of diluted solution is $0.28\times 10^{-5}M$

2) On further dilution

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = $0.28\times 10^{-5}M$

$V_1$ = volume of stock solution = 3.00 ml

$M_2$ = molarity of diluted solution = ?

$V_2$ = volume of diluted solution = 25.00 ml

$0.28\times 10^{-5}M\times 3.00=M_2\times 25.00$

$M_2=0.034\times 10^{-5}M$

Therefore, the concentration of diluted solution is $0.034\times 10^{-5}M$

3) On further dilution

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = $0.034\times 10^{-5}M$

$V_1$ = volume of stock solution = 3.00 ml

$M_2$ = molarity of diluted solution = ?

$V_2$ = volume of diluted solution = 25.00 ml

$0.034\times 10^{-5}M\times 3.00=M_2\times 25.00$

$M_2=4.0\times 10^{-8}M$

Therefore, the concentration of final solution is $4.0\times 10^{-8}M$

5 0

3 years ago

The table shows several useful salts formed from reactions between different acids and bases.

ollegr [7]

The two chemical formulas which will correctly complete the table for lithium fluoride are: A. HF, LiOH.

<h3>What is a chemical reaction?</h3>

A chemical reaction can be defined as a chemical process that involves the continuous transformation (rearrangement) of the ionic, atomic or molecular structure of a chemical element by breaking down and forming chemical bonds, in order to produce a new chemical compound while new bonds are formed.

This ultimately implies that, chemical bonds between atoms of a chemical element are broken and then new bonds are formed in all chemical reactions.

<h3>What is a neutralization reaction?</h3>

A neutralization reaction can be defined as a type of chemical reaction between an acid and a base, which typically leads to the formation of an ionic compound (salt) and water as end products as shown below:

LiOH(aq) + HF(aq) → LiF(s) + H₂O(l)

In this context, we can infer and logically deduce that the two chemical formulas which will correctly complete the table for lithium fluoride are HF and LiOH.

Read more on neutralization reaction here: brainly.com/question/27745033

#SPJ1

3 0

2 years ago

A nanoparticle of pure metal A is a cube.

xxMikexx [17]

Answer:

8000nm^3

Explanation:

l x w x h = volume

20 x 20 x 20 = 8000nm

4 0

3 years ago