Answer:
339.2K
Explanation:
Using Charles law equation;
V1/T1 = V2/T2
Where;
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question,
V1 = 2.97 L
V2 = 3.42 L
T1 = 21.6°C = 21.6 + 273 = 294.6K
T2 = ?
Using V1/T1 = V2/T2
2.97/294.6 = 3.42/T2
Cross multiply
2.97 × T2 = 294.6 × 3.42
2.97T2 = 1007.532
T2 = 1007.532 ÷ 2.97
T2 = 339.236
The final temperature is 339.2K
Answer:
pH = 6.5
Explanation:
Given data:
pH of substance = ?
[OH⁻] concentration = 3.2×10⁻⁸
Solution:
pOH = -log[OH⁻]
pOH = -log[3.2×10⁻⁸]
pOH = 7.5
we know that,
pH + pOH = 14
pH = 14- pOH
pH = 14 - 7.5
pH = 6.5
Answer:
An Alkaline solution should be the answer to that.
The equilibrium constant expression is the ratio of the concentrations of the products over the reactants. Notice how each concentration of product or reactant is raised to the power of its coefficient. For example, the concentration of D is raised to the power of 3 since it is 3D in the balanced reaction.
Answer:
To prepare 20,0 mL of the liquid mixture you should mix 15,3 mL of CHCl₃ with 4,7 mL of CHBr₃
Explanation:
Here you have two variables: The volume of both CHCl₃ (X) and CHBr₃ (Y). To find these two variables you must have, at least, two equations.
You know total volume is 20,0 mL. Thus:
X + Y = 20,0 mL (1)
The other equation is:
× 1,492 g/mL + 
× 2,890 g/mL = 1,82 g/mL (2)
If you replace (1) in (2):
× 1,492 g/mL + 
× 2,890 g/mL = 1,82 g/mL
Solving:
X = 15,3 mL
Thus, using (1):
20,0 mL - 15,3 mL = Y = 4,7 mL
Thus, to prepare 20,0 mL of the liquid mixture you must mix 15,3 mL of CHCl₃ with 4,7 mL of CHBr₃.
I hope it helps!
