Answer:
n= -3
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
4n+2=6(
1
3
n−
2
3
)
4n+2=(6)(
1
3
n)+(6)(
−2
3
)(Distribute)
4n+2=2n+−4
4n+2=2n−4
Step 2: Subtract 2n from both sides.
4n+2−2n=2n−4−2n
2n+2=−4
Step 3: Subtract 2 from both sides.
2n+2−2=−4−2
2n=−6
Step 4: Divide both sides by 2.
2n
2
=
−6
2
n=−3
Let us say T= probability of head turning up = 1/2 in one toss
H = probability of a tail turning up = 1/2 in one toss
Then P (56 heads or more) =
1/2^100 [ C(100,56) + C(100,57) + C(100,58) + ....
C(100,98) + C(100,99) + C(100,100) ]
where C(N, R) = N ! / [ (N - R)! R! ] number of occurrances of R formed from
N tosses.
Answer:
3
Step-by-step explanation:
so.i think y=3x+b. I'm not completely sure but y2-y1 over x2-x1
Answer:
remainder = 122
Step-by-step explanation:
Using the remainder theorem to evaluate the remainder
Division by x - 3 , thus evaluate f(3) for remainder
f(3) = 3³ + 14(3)² - 7(3) - 10
= 27 + 126 - 21 - 10
= 122 ← remainder
Step-by-step explanation:
we can factor out z
so that'll be
z((1/m)-(1/n))=1
divide by the value in parentheses on both sides
z=1/((1/m)-(1/n))
I can't tell if there's more the problem wants you to do. I could rewrite the equation on paper more easily, but I don't have one on hand
