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yanalaym [24]
4 years ago
11

ANSWER PLEASE

Mathematics
2 answers:
shusha [124]4 years ago
7 0

Answer: cos R and sin N

Step-by-step explanation:

tiny-mole [99]4 years ago
6 0
The easiest way to get this problem correctly is by calculating the sines and cosines of all the angles in the choices then choosing the correct choice.

sin <span>∠MQP = sin(56) = 0.829
cos </span><span>∠N = cos(56) = 0.559
sin </span><span>∠R = sin(34) = 0.559
sin </span><span>∠N = sin(56) = 0.829
cos </span><span>∠N = cos(56) = 0.559
sin </span><span>∠M = sin(90) = 1
cos </span><span>∠R = cos(34) = 0.828

Based on these findings, it is obvious that sin </span>∠MQP is equal to cos ∠R and sin <span>∠N.
Thus, the correct choice is "d".</span>
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3 years ago
Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the
s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

F(x)=\sqrt{x-2}

G(x)=(x-2)^2

H(x)=x^2+2

We compose F(x) and G(x) to get:

(F\circ G)(x)=F(G(x))

(F\circ G)(x)=F((x-2)^2)

(F\circ G)(x)=\sqrt{(x-2)^2-2}

(F\circ G)(x)=\sqrt{x^2-4x+4-2}

(F\circ G)(x)=\sqrt{x^2-4x+2}

(F\circ G)(x)\ne x

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

(F\circ H)(x)=F(H(x))

(F\circ H)(x)=F(x^2+2)

(F\circ H)(x)=\sqrt{x^2+2-2}

We simplify to get:

(F\circ H)(x)=\sqrt{x^2}

(F\circ H)(x)=x

Since (F\circ H)(x)=x, H(x) is an inverse of F(x)

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3 years ago
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vaieri [72.5K]
Start at 4 and since it a negative go down one and over one
4 0
3 years ago
Read 2 more answers
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