The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
The center of the circle is expressed as (h,k) in the standard form of equation. In this case, the diameter endpoints are <span>(-3, 8) and (7, 4). Hence the circle center has coordinates which are the midpoints of the two points.
x = (-3 + 7) /2 = 2
y = (8 + 4) /2 = 6
hence the center of the circle is (2,6)</span>
We know,
1 MB = 1000 KB
513 MB = (1,000 * 513) KB
= 513,000 KB
Now,
1 KB = 1,000 bytes
513,000 KB = (1,000 * 513,000) bytes
= 513,000,000 bytes
∴ 513 MB is 513,000,000 bytes
Answer:
B.) x=5
Step-by-step explanation:
Use the Pythagorean theorem. Since it isosceles, both values of x are the same. Split 6 in half (because perpendicular bisector).Insert values:
X is equal to 5.
Done.
Answer:
50%
Step-by-step explanation:
Given that :
Let Probability of rain today = P(rain today) = 50% = 0.5
The complement of an event A denoted as A' means the opposite of event A is obtained by subtracting event a from 1.
P(rain today) = 0.5
The complement of P(rain today) ; means the probability that it will NOT rain today;
Hence, P(raintoday') = 1 - 0.5 = 0.5 = 50%
