) a rectangular box has length 12 inches, width 20 inches, and a height of 7 inches. find the angle between the diagonal of the
box and the diagonal of its base. the angle should be measured in radians.
1 answer:
We assume the base is 12 in × 20 in, so its diagonal has length
... √(12² +20²) = √(144 +400) = √544 = 4√34 . . . inches
Then the tangent of the angle of interest is the ratio of the box height to the base diagonal:
... tan(α) = (7 in)/(4√34 in) ≈ 0.300123
The angle will be the arctangent of this value,
... α = arctan(7/√544) ≈ 0.291569 radians
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Step-by-step explanation:
I think you mean a² + b² = c², not ca.
a = 10, c = 26
b² = c² - a² = 26² - 10² = 576
b = √576 = 24 ft
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Range: {-9, 4, 8}
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Step-by-step explanation:
