Answer:
Given that,
The number of grams A of a certain radioactive substance present at time, in years
from the present, t is given by the formula

a) To find the initial amount of this substance
At t=0, we get


We know that e^0=1 ( anything to the power zero is 1)
we get,

The initial amount of the substance is 45 grams
b)To find thehalf-life of this substance
To find t when the substance becames half the amount.
A=45/2
Substitute this we get,


Taking natural logarithm on both sides we get,







Half-life of this substance is 154.02
c) To find the amount of substance will be present around in 2500 years
Put t=2500
we get,




The amount of substance will be present around in 2500 years is 0.000585 grams
Answer: c = 9
Step-by-step explanation:
12-9=3+9=12
Answer:
Answer:
3.14159
Step-by-step explanation:
This number is pi. Pi goes on for millions of digits on end.
Step-by-step explanation:
Answer:
3/4
Step-by-step explanation:
as y goes up 3 x goes up 4