55. A rhombus has side length 10 cm, and the longer diagonal measuring 10 cm.

Janet and Patrick surveyed a total of 219 people. Out of the 137 girls who were surveyed, 28 said summer was their favorite seas

Nat2105 [25]

Answer: See figure 2 in the diagram below for the table.

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Explanation:

The steps are fairly lengthy to explain in words, but the process is fairly straightforward. Start with figure 1 in the diagram below. The letters A through O represent the steps you'll take to replace them. For instance, you'll replace A with 219 since that's the grand total. Then B is replaced with 137 since we're told that 137 girls were surveyed. Then C gets replaced with 219-137 = 82, and so on. Use arithmetic (adding and subtracting) to gradually replace each letter with the proper number as figure 2 shows. The alphabetical order directly corresponds to the order in which the values are given by your teacher (eg: 219 is first, then 137 next, and so on).

Let me know if you get stuck on any one step, or need me to go into more detail.

7 0

3 years ago

Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of

forsale [732]

Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

$n = 120, \pi = \frac{58}{120} = 0.4833$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a p-value of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001$

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

8 0

3 years ago

Can someone please help me on this

choli [55]

Answer:

if you flipped one of the figures you will see that they are both the same shape and the same distance from the x and y axes.

3 0

3 years ago

Surri solved the equation x ^ 2 equals 49 and found that x equals 7 what error did Suro make

denpristay [2]

It does not look like Suro even made an error. She took the square root of both sides to get x = 7, I don't see any problem here.