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2 years ago

Match each equation with a diagram:

Mathematics

2 answers:

SCORPION-xisa [38]2 years ago

5 0

B
D
A
C
In that order :)

denis23 [38]2 years ago

3 0

Answers:
Equation 1: B
Equation 2: D
Equation 3: A
Equation 4: C

*I am pretty sure are right

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Write 2^100 as an exponent with a base of: 32

jeka94

Answer:

32^20

Step-by-step explanation:

Here you can either:

Convert to logarthmic format and use base changing formula.

Simply do 2^100=32^x, find x.

I chose option 2 because its quicker here. However, it will not always work.

8 0

2 years ago

Pleaseeee help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

zzz [600]

Answer:

90 degrees

Step-by-step explanation:

triangles add up to 180 degrees so if triangle jkl is the same as triangle rst then you add 35 to 55 and you now have t isolated with 90 degrees left in your triangle so it's 90 degrees.

3 0

2 years ago

Combine any like terms in the expression. If there are no like terms, rewrite the expression.

stich3 [128]

Answer:

40w^3

Step-by-step explanation:

I'm assuming you meant w^3 (w to the third power). In that case, you would just add 34 + 13 + 11 - 18 because they are all like terms (coefficients of w^3).

5 0

1 year ago

For the function g(x)=3-8(1/4)^2-x

Reika [66]

Using function concepts, it is found that:

a) The y-intercept is y = 2.5.

b) The horizontal asymptote is x = 3.

c) The function is decreasing.

d) The domain is $(-\infty,\infty)$ and the range is $(-\infty,3)$ .
e) The graph is given at the end of the answer.

------------------------------------

The given function is:

$g(x) = 3 - 8\left(\frac{1}{4}\right)^{2-x}$

------------------------------------

Question a:

The y-intercept is g(0), thus:

$g(0) = 3 - 8\left(\frac{1}{4}\right)^{2-0} = 3 - 8\left(\frac{1}{4}\right)^{2} = 3 - \frac{8}{16} = 3 - 0.5 = 2.5$

The y-intercept is y = 2.5.

------------------------------------

Question b:

The horizontal asymptote is the limit of the function when x goes to infinity, if it exists.

$\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2+\infty} = 3 - 8\left(\frac{1}{4}\right)^{\infty} = 3 - 8\frac{1^{\infty}}{4^{\infty}} = 3 -0 = 3$

--------------------------------------------------

$\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2-\infty} = 3 - 8\left(\frac{1}{4}\right)^{-\infty} = 3 - 8\times 4^{\infty} = 3 - \infty = -\infty$

Thus, the horizontal asymptote is x = 3.

--------------------------------------------------

Question c:

The limit of x going to infinity of the function is negative infinity, which means that the function is decreasing.

--------------------------------------------------

Question d:

Exponential function has no restrictions in the domain, so it is all real values, that is $(-\infty,\infty)$ .
From the limits in item c, the range is: $(-\infty,3)$

--------------------------------------------------

The sketching of the graph is given appended at the end of this answer.

A similar problem is given at brainly.com/question/16533631

8 0

1 year ago

Solve the system of equations.

slavikrds [6]

A..... (im pretty sure)

8 0

2 years ago