Can u get this right?

Water is being split to form two new substances hydrogen and oxygen is this a change of state?

Stella [2.4K]

I'd say you haven't given us enough information to answer that.

When we talk about "change of state", we're talking about changes
between solid, liquid, and gas.

Tell us what the state of the water is, and what the states of the
hydrogen and oxygen are after the split, and we'll be able to
summarize the changes of state that may be taking place.

5 0

4 years ago

Stan walks 10km west to the grocery store. He shops then walks back 10 km east back to his house. What distance did he cover? Wh

Lesechka [4]

Stan’s displaceent is 0 km because he ends his walk where he started.

6 0

3 years ago

How quickly a leaf grows is proportional how big [ie the surface area] the leaf is. If the area of the leaf grows from 2cm2 to 3

marusya05 [52]

Answer: 9 days

Explanation:

Step 1

Let the rate of Leaf growth r be defined as, $\frac{Increase in area}{time taken}$ = $\frac{A1 - A}{t}$

where A is initial area of the leaf, A1 is the final area of the leaf and t is the time taken for the increase in Area.

Express the proportional relationship in equation.

Given that rate of leaf growth, r is proportional to the surface area of the leaf A. we have r ∝ A.

r = kA, where k is the rate constant.

therefore, k = $\frac{r}{A}$

when A = 2 $cm^{2}$ , A1 = 3

so k = $\frac{\frac{3 - 2}{3}}{2}$

= $\frac{1}{3}$ ÷ 2

= 0.33 ÷ 2

k = 0.167

After calculating the rate constant k, we then find the time t when A1 is 5 $cm^{2}$

we have r = k × A1 = $\frac{A1 - A}{t}$

so, 0.167 × 2 = $\frac{5 - 2}{t}$

0.33 = $\frac{3}{t}$ .

t = 3/0.33

Therefore, t = 9 days.

3 0

4 years ago

Two objects, A with charge +Q and B with charge +4Q, are separated by a distance r. The magnitude of the force exerted on the se

scZoUnD [109]

Answer:

The magnitude of electric force on object B due to object A when they are 2r distance apart is F/4.

Explanation:

Given :

Electric charge on object A = +Q

Electric charge on object B = +4Q

When the objects A and B are r distance apart, the magnitude of electrostatic force exerted on B due to A is given by the relation :

$F=\frac{1}{4\pi\epsilon_{0} } \frac{Q\times4Q}{r^{2} }$ .....(1)

Now, the two objects are apart by distance of 2r, hence the force acting on the object B due to A is :

$F_{1} =\frac{1}{4\pi\epsilon_{0} } \frac{Q\times4Q}{(2r)^{2} }$

$F_{1} =\frac{1}{4\pi\epsilon_{0} } \frac{Q\times4Q}{4r^{2} }$

Substitute equation (1) in the above equation.

$F_{1} =\frac{F}{4}$

6 0

3 years ago

Sometimes a person cannot clearly see objects close up or far away. To correct this type of vision, bifocals are often used. The

Tanzania [10]

Answer:

Top Half power is

$P_{top} = -0.58 dioptre$

Bottom half power

$P_{bottom} = +1.06 dioptre$

Explanation:

For the top part of the lens we need a focal length of the lens in which person can see upto a large distance

so here we have

$d_i = -171 cm$

$d_o = infinite$

now by lens formula

$\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}$

now we have

$f = d_i = -171 cm$

now power of top part of the lens is given as

$P = \frac{1}{f} = -0.58 Dioptre$

Now for the bottom half we can say

$d_o = 25 cm$

$d_i = -34 cm$

now by lens formula

$\frac{1}{25} - \frac{1}{34} = \frac{1}{f}$

$f = 94.4 cm$

$P = \frac{1}{f} = 1.06 Dioptre$

3 0

3 years ago