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My name is Ann [436]
4 years ago
13

How quickly a leaf grows is proportional how big [ie the surface area] the leaf is. If the area of the leaf grows from 2cm2 to 3

cm2 in 3 days, how long will it take for the leaf's area to increase to 5 cm2
Physics
1 answer:
marusya05 [52]4 years ago
3 0

Answer: 9 days

Explanation:

  • Step 1

Let the rate of Leaf growth <em>r</em> be defined as, \frac{Increase  in  area}{time taken} = \frac{A1 - A}{t}

where <em>A</em> is initial area of the leaf, <em>A1</em> is the final area of the leaf and<em> t</em> is the time taken for the increase in Area.

  • Express the proportional relationship in equation.

Given that rate of leaf growth, r is proportional to the surface area of the leaf A. we have r ∝ A.

r = kA, where k is the rate constant.

therefore, k = \frac{r}{A}

when A = 2cm^{2}, A1 = 3

so k = \frac{\frac{3 - 2}{3}}{2}

= \frac{1}{3} ÷ 2

= 0.33 ÷ 2

k = 0.167

  • After calculating the rate constant k, we then find the time t when A1 is 5cm^{2}
  • we have r = k × A1 = \frac{A1 - A}{t}

so, 0.167 × 2 = \frac{5 - 2}{t}

0.33 = \frac{3}{t}.

t = 3/0.33

Therefore, t = 9 days.

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3 years ago
An insulated lamp bulb is on the bottom of a swimming pool at a point 2.5 m from a wall; the pool is 2.5 m deep and filled to th
pashok25 [27]

Answer:

option A

Explanation:

given,

lamp position from pool wall = 2.5 m

height of the pool = 2.5 m

now,

tan \theta = \dfrac{P}{B}

\theta =tan^{-1}(\dfrac{2.5}{2.5})

\theta =45^0

from the triangle

θ = i = 45°

using Snell's law

n₁ sin i = n₂ sin r

n₁ =4/3     n₂ = 1  

now,

\dfrac{sin r}{sin i}=\dfrac{n_1}{n_2}

\dfrac{sin r}{sin 45^0}=\dfrac{\dfrac{4}{3}}{1}

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The second Law of Thermodynamics states that: A. spontaneous processes are characterized by the overall conversion of order to d
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Answer:

Spontaneous processes are characterized by the overall conversion of order to disorder.

Explanation:

The second law of thermodynamics states that: A spontaneous process occurs only if there is an increase in entropy of a system and its surroundings.

Entropy, S, is a measure of the randomness or disorder of a system. It is measured in J/Kmol.

The change in entropy, ∆S = ∆H/T

Where ∆H = change in enthalpy, T = Temperature in Kelvin.

For,

I. An endothermic reaction, ∆S = positive (that is, ∆S is greater than zero), there is an increase in entropy, therefore, the reaction is spontaneous.

II. An exothermic reaction, ∆S = negative (that is, ∆S is less than zero) there is a decrease in entropy, so, the reaction is non-spontaneous.

III. A system at equilibrium, ∆S = 0.

Then,

The standard change in entropy of a reaction, ∆So reaction , is the difference in the standard entropies between products and reactants:

∆So reaction = n ∆Soproducts - m ∆Soreactants

Where, = sigma = sum of,

∆ = delta = change in,

n and m = stoichiometric coefficients of the products and reactants respectively.

Furthermore, the entropy of the system and surroundings is referred to as the entropy of the universe.

∆Suniverse = ∆Ssurroundings + ∆Ssystem.

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