All categories

3 years ago

PLEASE HELP it should be easy for someone but I can’t do it

Mathematics

1 answer:

-Dominant- [34]3 years ago

8 0

Answer:

Total crackers on the plate are 12

Step-by-step explanation:

Manuel ate crackers = $\frac{1}{3}$

His brother ate crackers = $\frac{1}{4}$

Crackers left on the plate = 5

We need to find how many crackers were there on the plate.

Let x be the total crackers on the plate

So, we can write the equation

$x-\frac{1}{3}x-\frac{1}{4}x=5$

Because 1/3 and 1/4 crackers are eaten and 5 are left so, we subtract 1/3x and 1/4x from x and equal it to 5

$\frac{12x-4x-3x}{12}=5\\\frac{12x-7x}{12}=5\\\frac{5x}{12}=5\\x=\frac{5*12}{5}\\x=12$

So, we get x = 12

Therefore, total crackers on the plate are 12

You might be interested in

Suppose you are given either a fair dice or an unfair dice (6-sided). You have no basis for considering either dice more likely

hoa [83]

Answer: Our required probability is 0.83.

Step-by-step explanation:

Since we have given that

Number of dices = 2

Number of fair dice = 1

Probability of getting a fair dice P(E₁) = $\dfrac{1}{2}$

Number of unfair dice = 1

Probability of getting a unfair dice P(E₂) = $\dfrac{1}{2}$

Probability of getting a 3 for the fair dice P(A|E₁)= $\dfrac{1}{6}$

Probability of getting a 3 for the unfair dice P(A|E₂) = $\dfrac{1}{3}$

So, we need to find the probability that the die he rolled is fair given that the outcome is 3.

So, we will use "Bayes theorem":

$P(E_1|A)=\dfrac{P(E_1)P(A|E_1)}{P(E_1)P(A|E_1)+P(E_2)P(A|E_2)}\\\\(E_1|A)=\dfrac{0.5\times 0.16}{0.5\times 0.16+0.5\times 0.34}\\\\P(E_1|A)=0.83$

Hence, our required probability is 0.83.

8 0

3 years ago

Find the error & find the correct answer 2In(x)=In(3x)-[In(9)-2In(3)] In(x^2)=In(3x)-[In(9)-In(9)] In(x^2)=In(3x)-0 In(x^2)=

Art [367]

Answer:

Error: $lnx^2=ln 3x$ not $ln\frac{3x}{0}$

Solution:x=0 and 3

Step-by-step explanation:

We have to find the error and correct answer

Given: $2ln x=ln(3x)-[ln9-2ln(3)]$

$lnx^2=ln(3x)-[ln9-ln3^2]$

Using the formula

$alog b=logb^a$

$lnx^2=ln(3x)-[ln9-ln9]$

$lnx^2=ln(3x)-0$

$lnx^2=ln(3x)$

$x^2=3x$

$x^2-3x=0$

$x(x-3)=0$

Therefore, x=0 and x=3

But last step in the given solution

$lnx^2=ln\frac{3x}{0}=\infty$

It is wrong this property is used when

$log m-log n$ then

$log\frac{m}{n}$

Hence, the student wrote $lnx^2=ln\frac{3x}{0}$ instead of $lnx^2=ln3x$ and solution is given by

x=0 and x=3

4 0

3 years ago

Which equation best matches the graph shown below?

n200080 [17]

Answer:

y= 0.2(x+1)^2+5 (Bottom left answer)

Step-by-step explanation:

Hope this helps :)

6 0

2 years ago

he box plot represents the number of minutes it takes for the students in a class to run a mile. What is the minimum of the data

Elis [28]

It's 5. Just took this test and got this question right :)

7 0

3 years ago

Read 2 more answers

Find the unit rate.<br> 180 miles in 3 hours

leva [86]

Answer:

60 miles per hour

Step-by-step explanation:

First, put the equation in a fraction.

You would put 180 up top because people always say miles per hour not the other way around.

You can see the dividing line as your "per" and your "hour" would be the bottom number.

To find the unit rate, you will divide the numerator (180) and the denominator (3).

Your final answer should be 60 miles per hour.

$\frac{180}{3} = \frac{60}{1}= 60$

3 0

3 years ago