Since y is .95 and x is 1 it is a unit rate which is the constant of proportionality.
Correct me if I am wrong.
Answer:
65
Step-by-step explanation:
180-115=65 bc all the lines are parallel.
Answer:
where −5 ≤ x ≤ 3
Step-by-step explanation:
The given function is 
.
We want to select the option that describes all the solutions to the parabola.
The domain of the parabola is −5 ≤ x ≤ 3.
This means that any x=a on −5 ≤ x ≤ 3 that satisfies (a,f(a)), is a solution.
This can be rewritten as 
Therefore for x belonging to −5 ≤ x ≤ 3, all solutions are given by:
where −5 ≤ x ≤ 3.
Ts temperature as a function of time is given by T(t)=a(1-e^kt)+b
the values of a and b area = 50 Fb = 350 F
this is very evident to equation the b is the initial temperatre of the oven which is 350 F
and also a is the initial temperature of the potato because it is the term multiplied by the exponent term which will indicate the temperature increasse of the potato
Answer:
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Step-by-step explanation:
for
I= ∫x^n . e^ax dx
then using integration by parts we can define u and dv such that
I= ∫(x^n) . (e^ax dx) = ∫u . dv
where
u= x^n → du = n*x^(n-1) dx
dv= e^ax dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)
then we know that
I= ∫u . dv = u*v - ∫v . du + C
( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =
(u*v) - ∫v*du + C )
therefore
I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
