Question

Can anyone help me with this problem by factoring and list the steps please

Answer 1

Answer:

$m=2, m=0$

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$20m^2-40m=0$

Use quadratic formula:-

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$m_1,_2=\frac{-(-40) -+\sqrt{x} (-40)^2-4*20*0}{2*20}$

$\sqrt{(-40)^2-4*20*0}=40$

$m_1,_2=\frac{-(-40)-,+40}{2*20}$

$m_1=\frac{-(-40)+40}{2*20},m_1=\frac{-(-40)-40}{2*20}$

$m=\frac{-(-40)+40}{2*20}:2$

$m=\frac{-(-40)-40}{2*20}:0$

$m=2, m=0$

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hope it helps...

have a great day!!