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polet [3.4K]
3 years ago
11

Pls help. ............. ​

Mathematics
2 answers:
Llana [10]3 years ago
8 0
(4, 2.5) is the coordinate location of the variable Q :D
tatiyna3 years ago
6 0

Answer:

(4,2.5)

Step-by-step explanation:

You might be interested in
Find a formula for the nth term in this
stepan [7]

The formula of nth term is  = 10 - 3n

What is AP?

  • A series of numbers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms. Take the numbers 5, 7, 9, 11, 13, and 15 as an example. . . is a sequence of numbers having a common difference of two.
  • The n-th term of the sequence is given by:, if the beginning term of an arithmetic progression is and the common difference between succeeding members is, then
  • If the AP contains m phrases, then denotes the final term, which is given by:
  • The term "finite arithmetic progression" or "arithmetic progression" refers to a finite segment of an arithmetic progression. An arithmetic series is the total of a finite arithmetic progression.

Acc to our question-

  • For the nth term in an algebraic series
  • U(n) = a + (n - 1)d
  • the number of terms is n.
  • The first term is a.
  • d is the typical difference
  • From the preceding sequence
  • a = 7
  • d = 4 - 7 = - 3
  • The nth term's formula is
  • U(n) = 7 + (n - 1)-3
  • = 7 - 3n + 3
  • The ultimate solution is
  • = 10 - 3n

Hence,The formula of nth term is  = 10 - 3n

learn more about AP click here:

brainly.com/question/6561461

#SPJ13

3 0
1 year ago
Help me please I beg
Readme [11.4K]

As far as I understand A)

4 0
3 years ago
A formal garden has 3 sections of different colored tulips. Each section has 162 tulips.
Anettt [7]
486 if your looking for the total
3 0
3 years ago
The following sequence of numbers is an arithmetic sequence.
Georgia [21]
The answer would be True because the sequence is constant
8 0
3 years ago
What does not represent the quotient of 17 divided by 10?
amm1812
17-10= j      i really don't know i just guessed  
7 0
3 years ago
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