Answer:
<em>Correct choice: B</em>
Step-by-step explanation:
<u>System of non-linear equations</u>
It's given the following system of equations:
We'll use the substitution method. Substituting y from the first equation into the second equation, we have:
Moving all terms to the left side:
Simplifying:
Factoring:
There are two solutions:
x=-4, x=2
The first solution gives a value for y:
y=-4+13=9
First solution: (-4,9)
The second solution gives a value for y:
y=2+13=15
Second solution: (2,15)
Correct choice: B
Answer:
looks hard
Step-by-step explanation:
The greatest number can be as large as 81.
<u>Step-by-step explanation:</u>
Given that,
- A set of five different positive integers has a mean of 33 and a median of 40.
- We need to find the set of five different positive integers.
We already know that,
- The term "median" is the middle term which is 40.
- Therefore, if you do not include 0 in positive integers, then the first two positive integers below the median value of 40 to be as low as possible are 1 and 2.
- The median 40 will be the third positive integer of the set.
- Therefore, the fourth positive integer should be the next lowest possible value of 40 which is 41.
With simple algebra you can figure out the last greater number.
-
The set of five different positive integers is given as {1,2,40,41,x}.
- Let, x be the last greater number in the set.
The term "mean" is defined as the sum of all the integers in the set divided by the number of integers in the set.
⇒ Mean = (1+2+40+41+x) / 5
⇒ 33 = (84+x) / 5
⇒ 33×5 = 84 + x
⇒ 165 - 84 = x
⇒ 81 = x
∴ The greatest number can be as large as 81.
Answer: Should be A, 12 - i
Step-by-step explanation:
Got it from another website lol