Question

PLEASE SOLVE FOR ME!!!! I am stuck on question... 36/5x - 10 < 5

Answer 1

$*\ \dfrac{36}{5x} - 10 \ \textless \ 5 \qquad x \neq 0 \\ \\ \\ \dfrac{36}{5x}\ \textless \ 5 + 10 \\ \\ \\ \dfrac{36}{5x}\ \textless \ 15 \\ \\ \\ 36\ \textless \ 15 * (5x) \\ \\ 36 \ \textless \ 75x \\ \\ \dfrac{36}{75}\ \textless \ x \qquad \dfrac{12}{25}\ \textless \ x \qquad \boxed{x\in ( \frac{12}{25}; +\infty) }$



 $*\ \dfrac{36}{5x-10} \ \textless \ 5 \qquad x \neq 2 \\ \\ \\36 \textless \ 5 (5x-10) \\ \\ 36 \textless \ 25x-50 \\ \\ 36+50\ \textless \25x \\ \\ 86 \ \textless \ 25x \\ \\ \dfrac{86}{25}\ \textless \ x\qquad \to \qquad \boxed{x\in ( \frac{86}{25}; +\infty) }$