Question

Solve the following quadratic equation for all values of x in simplest form. 4(3x - 5)/1+5 = 13

Answer 1

To find :

• The value of x.

Solving the equation :

$\longmapsto \sf { \dfrac{4(3x-5)}{1+5} = 13}$

$\longmapsto \sf { \dfrac{12x-20}{6} = 13}$

$\longmapsto$ 12x - 20 = 6 × 13

$\longmapsto$ 12x - 20 = 78

$\longmapsto$ 12x = 78 + 20

$\longmapsto$ 12x = 98

$\longmapsto$ x =$\sf { \dfrac{98}{12} }$

• Divide the numerator and the denominator in R.H.S by 2.

$\longmapsto \bf\red { x = \dfrac{49}{6} }$

Value of x is 49/6.

Answer 2

Answer:

• ${\boxed{\sf{\gray{x = \dfrac{49}{6}}}}}$

Step-by-step explanation:

${\underline{\underline{\bf{\red{\:\:\:Given\: Equation\:\:\:}}}}}$

$\mapsto\:\:\sf{\dfrac{4(3x-5)}{1+5}=13}$

• We need to find the value of x in the given equation.

${\underline{\underline{\bf{\blue{\:\:\:Solution\:\:\:}}}}}$

______________________

$\qquad:\longrightarrow\:\:\:\:\sf\red{\dfrac{4(3x-5)}{1+5}=13}$

$\qquad:\longrightarrow\:\:\:\:\sf\orange{\dfrac{4(3x-5)}{6}=13}$

$\qquad:\longrightarrow\:\:\:\:\sf\green{\dfrac{2(3x-5)}{3}=13}$

$\qquad:\longrightarrow\:\:\:\:\sf\blue{\dfrac{6x-3}{10}=13}$

$\qquad:\longrightarrow\:\:\:\:\sf\purple{6x-10=39}$

$\qquad:\longrightarrow\:\:\:\:\sf\red{6x = 39+10}$

$\qquad:\longrightarrow\:\:\:\:\sf\blue{6x = 49}$

$\qquad:\longrightarrow\:\:\:\:{\underline{\boxed{\sf{\purple{x = \dfrac{49}{6}}}}}}$

______________________