To model this situation we are going to use the exponential decay function:

where

is the final amount remaining after

years of decay

is the initial amount

is the decay rate in decimal form

is the time in years
For substance A:
Since we have 300 grams of the substance,

. To convert the decay rate to decimal form, we are going to divide the rate by 100%:

. Replacing the values in our function:



equation (1)
For substance B:
Since we have 500 grams of the substance,

. To convert the decay rate to decimal form, we are going to divide the rate by 100%:

. Replacing the values in our function:



equation (2)
Since they are trying to determine how many years it will be before the substances have an equal mass

, we can replace

with

in both equations:

equation (1)

equation (2)
We can conclude that the system of equations that can be used to determine <span>how long it will be before the substances have an equal mass, </span>

, is:

Solving the system, we can show that it will take approximately 231.59 years for that to happen.