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3 years ago

Which is an expression in square units that represents the area of the shaded segment of center ofOC

Mathematics

1 answer:

Helen [10]3 years ago

4 0

9514 1404 393

Answer:

Step-by-step explanation:

The formula for the area of a segment is ...

A = 1/2r²(θ -sin(θ))

for radius r and central angle θ.

Here, we have θ = π/2, so this becomes ...

A = 1/2r²(π/2 -1) . . . . . matches choice D

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Please explain as well, solve the trigonometric equation

aliina [53]

Given:

The trigonometric equation is:

$\tan x\sin x=\tan x\cos x$

To find:

The solutions for the given equation over $0^\circ$ .

Solution:

We have,

$\tan x\sin x=\tan x\cos x$

It can be written as

$\tan x\sin x-\tan x\cos x=0$

$\tan x(\sin x-\cos x)=0$

$\tan x=0$ and $(\sin x-\cos x)=0$

The solutions over $0^\circ$ are:

$x=90^\circ,180^\circ$ and $\sin x=\cos x$

$x=90^\circ,180^\circ$ and $x=45^\circ, 225^\circ$

Therefore, the correct option is D.

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3 years ago

What is the opportunity cost in this scenario? Harry has been very busy at work for the past two weeks. He has been working week

Afina-wow [57]

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3 years ago

Read 2 more answers

Write an expression to represent:<br> One less than the quotient of four and a number x.

sveticcg [70]

Answer:

4/x-1 is the correct answer

Step-by-step explanation:

3 0

4 years ago

Q4<br> Help pleaseeeeeeee

emmasim [6.3K]

a. The general equation for a circle centered at $(a,b)$ with radius $r$ is

$(x-a)^2+(y-b)^2=r^2$

The described circle has equation

$(x+3)^2+(y+2)^2=r^2$

We know the circle passes through the origin. This means that the equation above holds for $x=0$ and $y=0$ . The distance between any point on the circle and its center is the radius, so we can use this fact to determine $r$ :

$(0+3)^2+(0+2)^2=r^2\implies 9+4=13=r^2\implies r=\sqrt{13}$

So the circle's equation is

$(x+3)^2+(y+2)^2=(\sqrt{13})^2=13$

b. If the distance between point B and the center is less than $\sqrt{13}$ , then B lies inside the circle. If the distance is greater than $\sqrt{13}$ , it falls outside the circle. Otherwise, if the distance is exactly $\sqrt{13}$ , then B lies on the circle.