Answer:
7.211103
Step-by-step explanation:
For:
(X1, Y1) = (-3, 4)
(X2, Y2) = (1, -2)
Distance Equation Solution:
d=(1−(−3))2+(−2−4)2−−−−−−−−−−−−−−−−−−−√
d=(4)2+(−6)2−−−−−−−−−−√
d=16+36−−−−−−√
d=5–√2
d=7.211103
:)
Answer:
0.20p + 7 = 0.30p + 5
Step-by-step explanation:
- I
- took
- the
- test
- Enjoy!
- UwU
Answer:
6%
Step-by-step explanation:
Interest = Principal * rate * time
156 = 520(r)(5)
156 = 2600r
r = 0.06 or 6%
I need help Over the next two days, Benton Employment Agency is interviewing clients who
wish to find jobs. On the first day, the agency plans to interview clients in groups
of 6. On the second day, the agency will interview clients in groups of 8. If the
employment agency will interview the same number of clients on each day, what
is the smallest number of clients that could be interviewed each day?
Answer with explanation:
Given : Number of men = 4
Number of women = 6
Total people = ![6+4=10](https://tex.z-dn.net/?f=6%2B4%3D10)
Total number of ways to make a committee of five people from 10 persons :-
![^{10}C_{4}=\dfrac{10!}{4!(10-4)!}=210](https://tex.z-dn.net/?f=%5E%7B10%7DC_%7B4%7D%3D%5Cdfrac%7B10%21%7D%7B4%21%2810-4%29%21%7D%3D210)
a) Number of ways to make committee that has exactly four women :
![^6C_4\times ^4C_1=\dfrac{6!}{4!(6-4)!}\times4=60](https://tex.z-dn.net/?f=%5E6C_4%5Ctimes%20%5E4C_1%3D%5Cdfrac%7B6%21%7D%7B4%21%286-4%29%21%7D%5Ctimes4%3D60)
The probability that committee has exactly four women :
![\dfrac{60}{210}=\dfrac{2}{7}](https://tex.z-dn.net/?f=%5Cdfrac%7B60%7D%7B210%7D%3D%5Cdfrac%7B2%7D%7B7%7D)
b) Number of ways to make committee that has at-least four women :
![^6C_4\times ^4C_1+^6C_5=\dfrac{6!}{4!(6-4)!}\times4+6=66](https://tex.z-dn.net/?f=%5E6C_4%5Ctimes%20%5E4C_1%2B%5E6C_5%3D%5Cdfrac%7B6%21%7D%7B4%21%286-4%29%21%7D%5Ctimes4%2B6%3D66)
The probability that committee at-least four women :
![\dfrac{66}{210}=\dfrac{22}{70}](https://tex.z-dn.net/?f=%5Cdfrac%7B66%7D%7B210%7D%3D%5Cdfrac%7B22%7D%7B70%7D)
c) Number of ways that committee has more than 4 women :-
![^6C_5\times^4C_0=6](https://tex.z-dn.net/?f=%5E6C_5%5Ctimes%5E4C_0%3D6)
The probability that committee has more than 4 women :-
![\dfrac{6}{210}](https://tex.z-dn.net/?f=%5Cdfrac%7B6%7D%7B210%7D)
Now, the probability that committee has at most four women :-
![1-\dfrac{6}{210}=\dfrac{204}{210}=\dfrac{102}{105}](https://tex.z-dn.net/?f=1-%5Cdfrac%7B6%7D%7B210%7D%3D%5Cdfrac%7B204%7D%7B210%7D%3D%5Cdfrac%7B102%7D%7B105%7D)