9514 1404 393
Answer:
a) x = -3
b) y = (28/27)x -27
Step-by-step explanation:
a) College street has a slope of 0, so is a horizontal line. 2nd Ave is perpendicular, so is a vertical line, described by an equation of the form ...
x = constant
For 2nd Ave to intersect the point (-3, 1), the constant must match that x-coordinate. The equation is ...
x = -3
__
b) Since Ace Rd is perpendicular to Davidson St, its slope will be the opposite reciprocal of the slope of Davidson St. The slope of Ace Rd is ...
m = -1/(-27/28) = 28/27
Using the point-slope equation for a line, we can model Ace Rd as ...
y -y1 = m(x -x1)
y -1 = (28/27)(x -27)
y = (28/27)x -27
Answer:
x= -6
Step-by-step explanation:
y=4x-6
y=5x, so where ever you see y, put 5x there.
hence, 5x=4x-6
5x-4x=-6
x= -6
Answer:
Option D. minimum value at −38
Step-by-step explanation:
we have

Let

Complete the square




------> equation of a vertical parabola in vertex form
The vertex is the point 
The parabola open upward-----> the vertex is a minimum
therefore
minimum value at −38
Answer: (-3,4) and (9,20)
I think these two points will make the answer you have been looking for.