Initial velocity (u) = 2 m/s
Acceleration (a) = 10 m/s^2
Time taken (t) = 4 s
Let the final velocity be v.
By using the equation,
v = u + at, we get
or, v = 2 + 10 × 4
or, v = 2 + 40
or, v = 42
The final velocity is 42 m/s.
Answer:
For object A
m = 5 kg , v= -11 j
For B object
m = 6 kg , v= 5 i +8.7 j
For object C
m = 10 kg , v= -10 i
We know that
Linear momentum P= m v kg.m/s
a) A and C
Momentum in y direction
Py=- 5 x 11 j= - 55 j kg.m/s
Momentum in x direction
Px=- 10 x 10 j= - 100 i kg.m/s
b) B and C
Momentum in y direction
Py=6 x 8.7 j= 52.2 j kg.m/s
Momentum in x direction
Px=( 6 x 5 - 10 x 10 ) i = - 70 i kg.m/s
c) A ,B and C
By using data of a and b
Momentum in y direction
Py= 6 x 8.7 - 5 x 11 j= -2.8 j kg.m/s
Momentum in x direction
Px= 6 x 5 -10 x 10 i = -70 i kg.m/s
Answer:
YES! you do have the right answer
Explanation:
Answer: Option (C) is the correct answer.
Explanation:
Whether an acid is weak or strong it will cause harm if it comes in direct contact with the skin, eyes or mouth etc.
Thus, in order to prevent oneself, it is advised to wear a lab coat while working in laboratory as acids break down fabrics and can cause burns if the acids are strong.
Hence, a lab coat acts as a protective layer on the clothes so that even if acid falls on it then it might not reach the skin immediately and on time prevention can be taken.
Answer:
Explanation:
We shall consider a Gaussian surface inside the insulation in the form of curved wall of a cylinder having radius equal to 3mm and unit length , length being parallel to the axis of wire .
Charge inside the cylinder = 250 x 10⁻⁹ C .
Let E be electric field at the curved surface , perpendicular to surface .
Total electric flux coming out of curved surface
= 2π r x 1 x E
= 2 x 3.14 x 3 x 10⁻³ E
According to Gauss's theorem , total flux coming out
= charge inside / ε ( 250 x 10⁻⁹C charge will lie inside cylinder )
= 250 x 10⁻⁹ / 2.5 x 8.85 x 10⁻¹² ( ε = 2.5 ε₀ = 2.5 x 8.85 x 10⁻¹² )
= 11.3 x 10³ weber .
so ,
2 x 3.14 x 3 x 10⁻³ E = 11.3 x 10³
E = 11.3 x 10³ / 2 x 3.14 x 3 x 10⁻³
= .599 x 10⁶ N /C .
