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LuckyWell [14K]
1 year ago
5

When collecting a gas over water, the gas is always a mixture of the gas collected and water vapor.

Physics
1 answer:
bagirrra123 [75]1 year ago
7 0

When collecting a gas over water, the gas is always a mixture of the gas collected and water vapor. This statement is True

Water vapour or aqueous vapour is the name for the gaseous state of water. It is a particular kind of water condition inside the hydrosphere. Both the boiling and evaporation of liquid water as well as the sublimation of ice can produce water vapour. Water vapour is transparent, like the bulk of other atmospheric constituents. An example of water vapour is the mist that floats over a pot of boiling water.

<h3>What is Water vapor ?</h3>

The gaseous phase of water is known as water vapour, water vapour, or aqueous vapour. Within the hydrosphere, it is one type of water state. Water vapour can be created by the boiling or evaporation of liquid water as well as by the sublimation of ice. Like the majority of other atmospheric elements, water vapour is transparent.

Learn more about Water vapor here:

brainly.com/question/422363

#SPJ4

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The child's linear speed is
              
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3 years ago
Which type of rock is made of tiny bits of animal shells? A. gabbro B. coquina C. clastic sandstone D. limestone
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3 years ago
Read 2 more answers
A thin, metallic spherical shell of radius 0.347 m0.347 m has a total charge of 7.53×10−6 C7.53×10−6 C placed on it. A point cha
USPshnik [31]

Answer:

E = 12640.78 N/C

Explanation:

In order to calculate the electric field you can use the Gaussian theorem.

Thus, you have:

\Phi_E=\frac{Q}{\epsilon_o}

ФE: electric flux trough the Gaussian surface

Q: net charge inside the Gaussian surface

εo: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2

If you take the Gaussian surface as a spherical surface, with radius r, the electric field is parallel to the surface anywhere. Then, you have:

\Phi_E=EA=E(4\pi r^2)=\frac{Q}{\epsilon_o}\\\\E=\frac{Q}{4\pi \epsilon_o r^2}

r can be taken as the distance in which you want to calculate the electric field, that is, 0.795m

Next, you replace the values of the parameters in the last expression, by taking into account that the net charge inside the Gaussian surface is:

Q=7.53*10^{-6}C+3.65*10^{-6}C=1.115*10^{-5}C

Finally, you obtain for E:

E=\frac{1.118*10^{-5}C}{4\pi (8.85*10^{-12C^2/Nm^2})(0.795m)^2}=12640.78\frac{N}{C}

hence, the electric field at 0.795m from the center of the spherical shell is 12640.78 N/C

3 0
3 years ago
You are holding one end of an elastic cord that is fastened to a wall 3.0 m away. You begin shaking the end of the cord at 2.3 H
Karo-lina-s [1.5K]

Answer:

Time take to fill the standing wave to the entire length of the string is 1.3 sec.

Explanation:

Given :

The length of the one end x= 3m, frequency of the wave f = 2.3 Hz, wavelength of the wave λ = 1 m.

Standing wave is the example of the transverse wave, standing wave doesn't transfer energy in a medium.

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