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2 years ago

An object is most likely to sink in water if

Physics

2 answers:

LiRa [457]2 years ago

8 0

Answer:

High density D answers to your questions

bixtya [17]2 years ago

3 0

Answer: D, high density.

Explanation: In order for an object to float in water, its density must be lower than that of the water itself. And although something with high mass may have high density, these two factors are not directly proportionate. I can't lift an entire tree log, but it will still float.

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As an intern with an engineering firm, you are asked to measure the moment of inertia of a large wheel, for rotation about an ax

AysviL [449]

Answer:

$I=2.766\ kg.m^2$

Explanation:

We have:

diameter of the wheel, $d=0.88\ m$

weight of the wheel, $w_w=280\ N$

mass of hanging object to the wheel, $m_o=6.32\ kg$

speed of the hanging mass after the descend, $v_o=4\ m.s^{-1}$

height of descend, $h=2.5\ m$

(a)

moment of inertia of wheel about its central axis:

$I=\frac{1}{2} m.r^2$

$I=\frac{1}{2} \frac{w_w}{g}.r^2$

$I=\frac{1}{2} \times \frac{280}{9.8}\times 0.44^2$

$I=2.766\ kg.m^2$

3 0

3 years ago

What is the heat capacity of an object at 25.5∘C that absorbs 45 kJ of heat and is heated to 28.2∘C?

sergey [27]

Answer:

16.6 kJ/°C

Explanation:

given,

Amount of heat absorbed = 45 kJ

initial temperature, T₁ = 25.5°C

final temperature, T₂ = 28.2°C

change in temperature = T₂ - T₁

= 28.2 - 25.5 = 2.7° C

$Heat\ capacity = \dfrac{Heat\ absorbed}{\Delta T}$

$Heat\ capacity = \dfrac{45\ kJ}{2.7}$

$Heat\ capacity = 16.6\ kJ/^0C$

Heat capacity of the object is equal to 16.6 kJ/°C

4 0

3 years ago

Read 2 more answers

If the inside of a container has a surface area of 20cm², what will be the pressure on each square inch of the container if 117.

egoroff_w [7]

Answer:

Explanation:

given :-

force applied = 117.6N

Area = 20 m^2

Pressure =?

solution:-

Pressure = Force / Area

= 117.6 N / 20 m^2

= 5.88 Pascals

Hope it helps :D!

Explanation:

6 0

1 year ago

A piece of amber is charged by rubbing with a piece of fur. If the net excess charge on the fur is 8.9 nC ( 8.9 10-9 C), how man

Alika [10]

Answer:

Number of electrons, $n=5.56\times 10^{10}$

Explanation:

Given that,

Charge on the fur, $q=8.9\ nC=8.9\times 10^{-9}\ C$

A piece of amber is charged by rubbing with a piece of fur. We need to find the electrons were added to the amber. It can be calculated using the quantization of charge as

q = n × e

Where

n is the number of electrons

e is the charge on electron

$n=\dfrac{q}{e}$

$n=\dfrac{8.9\times 10^{-9}}{1.6\times 10^{-19}}$

$n=5.56\times 10^{10}\ electrons$

So, $n=5.56\times 10^{10}\ electrons$ number of electrons are added to the amber. Therefore, this is the required solution.

7 0

3 years ago

Rahman drops two stones P and Q each of mass 1 kg and 2 kg simultaneously from

kolbaska11 [484]

This question involves the use of the equations of motion for vertical motion.

The time taken by the stones P and Q to reach the ground is the same, that is "2 s".

The velocity with which Q hits the ground is "20 m/s".

The time taken by the stones to reach the ground can be calculated by using the second equation of motion for the vertical motion:

$h = v_it+\frac{1}{2}gt^2$

For both the stones P and Q:

h = height = 20 m

$v_i$ = initial velocity = 0 m/s

t = time = ?

g = acceleration due to gravity = 10 m/s²

Therefore,

$20\ m = (0\ m/s)t+\frac{1}{2}(10\ m/s^2)(t)^2\\\\t = \sqrt{\frac{20\ m}{5\ m/s^2}}$

t = 2 s

Hence, the time taken by both the stones to reach the ground is the same.

To find the final velocity of stone Q we will use the first equation of motion for the vertical motion:

$v_f=v_i+gt\\v_f = 0\ m/s+(10\ m/s^2)(2\ s)\\v_f = 20\ m/s$

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

5 0

2 years ago