Hello Here we must use the equation of motion v^2 = u^2 + 2as; where v is final velocity, u is initial velocity, a is the acceleratoin and is the distance travelled. We select this one because the time of collision is unknown to us. We know the truck stopped so its final velocity is 0; thus v = 0. Converting the initial velocity to SI units, we get 3.89 m/s. The distance traveled, s, is 0.062 meters. Inserting all of these values into the equation, 0 = (3.89)^2 + 2(a)(0.062) and solving for a, we get a to be -122.0 ms^(-2) The negative sign indicates the acceleration is in the opposite direction to the initial motion, which means the truck decelerated. This is consistent with the given condition.
Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!
Explanation:
Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!