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2 years ago

What is the area of a rectangle if the length is (4x + 2) cm and a width of (5x – 3) cm

2 answers:

7 0

(4x + 2)(5x - 3)

Multiply:

4x(5x) = 20x^2
4x(-3) = -12x
2(5x) = 10x
2(-3) = -6

Combine Like Terms:

10x-12x = -2x

Answer:
20x^2 - 2x - 6

KiRa [710]2 years ago

4 0

Answer:

20x^2−2x−6

Step-by-step explanation:

(4x+2)(5x+−3)

=(4x)(5x)+(4x)(−3)+(2)(5x)+(2)(−3)

=20x2−12x+10x−6

=20x2−2x−6

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2 years ago

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Alexus [3.1K]

Answer:

a)6

b)v^2-u^2/2a

Step-by-step explanation:

a)Given that,

u=12

a= -6

s=9

We know that,

v^2=u^2+2as

or, v^2=(12)^2+2×(-6)×9

or,v^2=144-108

or,v^2=36

or, v=√36

∴v=6

(Ans)

b)If ,v^2=u^2+2as

then, u^2+2as=v^2

or,2as=v^2-u^2

or, s=v^2-u^2/2a

∴s=v^2-u^2/2a

Hope ya find it helpful.. Thanks a lot...

6 0

2 years ago

the length , breadth and height of a cuboid is 2x^2y cm,5y^2z cm and 4z^2x cm. The volume of the cuboid is ...............

kondor19780726 [428]

For this case we have that by definition, the volume of a cuboid is given by:

$V = L * A * h$

Where:

L: It's the long

A: It is the width

h: It is the height

According to the problem data we have:

$L = 2x ^ 2y \ cm\\A = 5y ^ 2z \ cm\\h = 4z ^ 2x \ cm$

So, the volume of the cuboid is:

$V = (2x ^ 2y) (5y ^ 2z) (4z ^ 2x)\\V = 10x ^ 2y ^ 3z (4z ^ 2x)\\V = 40x ^ 3y ^ 3z ^ 3$

Finally, the volume of the cuboid is: $V = 40x ^ 3y ^ 3z ^ 3$

Answer:

$V = 40x ^ 3y ^ 3z ^ 3$

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