Answer:
The three numbers are 56/5, -39/5 and 78/5.
Step-by-step explanation:
EQUATION 1:
First number: x
Second number: y
Third number: z
x + y + z = 19
EQUATION 2:
Sum of following is 77
Twice the first number: 2x
5 times the second number: 5y
6 times the third number: 6z
So, 2x + 5y + 6z = 77
EQUATION 3:
Difference between first and second number is 19.
x - y = 19
Equation 1: x + y + z = 19
Equation 2: 2x + 5y + 6z = 77
Equation 3: x - y = 19
1. Find x in terms of y
x - y = 19
x = 19 + y
2. Find y in terms of z by putting the value of x in first and second equation
x + y + z = 19
(19 + y)+ y + z = 19
2y + z = 19 - 19
2y + z = 0
y = -z/2
and
2(19+y)+5y+6z=77
now putting the value of y in this equation
2(19-z/2)+5(-z/2)+6z=77
38 - z -5z/2 +6z = 77
5z/2 + 38 = 77
5z/2 = 39
z = 78/5
Now, y = -z/2
y = (-78/5)/2
y = -39/5
and x = 19 + y
x = 19 - 39/5
x = 56/5
Therefore, the three numbers are 56/5, -39/5 and 78/5.
Keyword: Sum
Learn more about sum at
brainly.com/question/10666510
brainly.com/question/4034547
#LearnwithBrainly
