Answer:
2,081,303
Step-by-step explanation:
x^2 - 4
------------------------------
x + 7 | x^3 + 7x^2 - 4x - 28
x^3 + 7x^2
------------------
0 - 4x - 28
-4x - 28
-------------
0
Now we know that
x^3 + 7x^2 - 4x - 28 = (x^2 - 4)(x + 7)
x^2 - 4 can be factored since it is the difference of two squares.
x^2 - 4 = (x + 2)(x - 2)
The complete factoring is:
x^3 + 7x^2 - 4x - 28 = (x +2)(x - 2)(x + 7)
I believe the answer is 2 to the twelfth power over 3
Step-by-step explanation:
|x-4|=6x+16 To find the absolute value :
x - 4 = 6x + 16 or x - 4 = -6x - 16 for first equation
x - 4 = 6x + 16 export like terms to the same side of the equation
-4 - 16 = 6x - x (The terms chages signs from negative to positive and from positive to negative when exported to the other sideof the equation)
-20 = 5x divide by 5
-4 = x
For the second equation
x - 4 = -6x - 16 export like terms to the same side of the equation
x + 6x = -16 + 4
7x = -12
x = 1.7 approximately
Answer:
40.08$ is your answer
Step-by-step explanation: