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Semmy [17]
2 years ago
7

Using mean and mean absolute deviation to compare data iready quiz answers

Mathematics
2 answers:
Marizza181 [45]2 years ago
7 0

The mean of a data us the addition of all numbers in the data set and then dividing them by the number of values in a set.

<h3>What is a mean?</h3>

Your information is incomplete. Therefore, an overview will be given. It should be noted that a mean simply means the average of a set of numbers that are given.

For example, if we have the following numbers:

3, 9, 4, 1, and 3. The mean will be:

= (3 + 9 + 4 + 1 + 3)/5

= 4

The mean absolute deviation is the average distance between the data points and the mean.

Learn more about mean on:

brainly.com/question/1136789

yKpoI14uk [10]2 years ago
6 0

There is a small difference in the mean number of stray cats rescued by a new leash at the animal clinic each week and the mean number of stray cats taken in by no ruff stuff animal hospital each week.

<h3>What is mean?</h3>

Mean is nothing but the average of the given set of values. It denotes the equal distribution of values for a given data set.

For the first case;

Mean = (13*5 + 14*10 + 15*19 + 16*13 + 17*4)/75 = 10.21

For the second case;

Mean =(3*2 + 4*10 + 5*21 + 6*11 + 7*5 + 8*3)/33 = 10.48

Hence, there is a small difference in the mean number of stray cats rescued by a new leash at the animal clinic each week and the mean number of stray cats taken in by no ruff stuff animal hospital each week.

To get more about the mean visit:

brainly.com/question/20436432

#SPJ4

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OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is <u>-20</u>.

Step-by-step explanation:

<u>Given</u> :

  • >> If for an A.P, d = -4

<u>To</u><u> </u><u>Find</u> :

  • >> T₂₀ - T₁₅

<u>Using Formula</u> :

General term of an A.P.

\star{\small{\underline{\boxed{\sf{\red{ T_n = a  + (n - 1)d}}}}}}

  • >> Tₙ = nᵗʰ term
  • >> a = first term
  • >> n = no. of terms
  • >> d = common difference

<u>Solution</u> :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

{\dashrightarrow{\pmb{\sf{ T_n = a  + (n - 1)d}}}}

{\dashrightarrow{\sf{ T_{20} = a  + (20 - 1) d}}}

{\dashrightarrow{\sf{ T_{20} = a  + (19)d}}}

{\dashrightarrow{\sf{ T_{20} = a  + 19  \times d}}}

{\dashrightarrow{\sf{ T_{20} = a  + 19d}}}

{\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a  + 19d}}}}}}

Hence, the value of T₂₀ is a + 19d.

\rule{190}1

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

{\dashrightarrow{\pmb{\sf{ T_n = a  + (n - 1)d}}}}

{\dashrightarrow{\sf{ T_{15}= a  + (15 - 1) d}}}

{\dashrightarrow{\sf{ T_{15}= a  + (14) d}}}

{\dashrightarrow{\sf{ T_{15}= a  + 14 \times d}}}

{\dashrightarrow{\sf{ T_{15}= a  + 14d}}}

{\star{\underline{\boxed{\sf \pink{ T_{15}= a  + 14d}}}}}

Hence, the value of T₁₅ is a + 14d

\rule{190}1

Now, finding the difference between T₂₀ - T₁₅ :

{\dashrightarrow{\pmb{\sf{T_{20} -  T_{15}}}}}

{\dashrightarrow{\sf{(a + 19d) -  (a + 14d)}}}

{\dashrightarrow{\sf{a + 19d -  a  -  14d}}}

{\dashrightarrow{\sf{a - a + 19d -  14d}}}

{\dashrightarrow{\sf{0+ 19d -  14d}}}

{\dashrightarrow{\sf{19d -  14d}}}

{\dashrightarrow{\sf{5 \times  - 4}}}

{\dashrightarrow{\sf{ - 20}}}

{\star \: \underline{\boxed{\sf{\pink{T_{20} -  T_{15} =  - 20}}}}}

Hence, the value of T₂₀ - T₁₅ is -20.

\underline{\rule{220pt}{3.5pt}}

3 0
2 years ago
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